- I do not follow this. Things in question are starred. (2^4 = 16 possibilities)
ID: 3866589 • Letter: #
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- I do not follow this. Things in question are starred.
(2^4 = 16 possibilities) (2^8 = 256) (2^16 = 65,536) (2^32 = 4,294,967,296)
- Sorry.. A 4-bit data word has only a 16-bit possibilty range. I'm trying to figure where does the 4096 (4K) / 8192 (8K) come from. I understand that 16-bits = 65536 and 32-bits = 4,294,967,296 (so no stars). I'm trying to follow where the numbers with stars came from. Thanks!
- Picking a specific example.. the first column. I'm seeing it as 4-bits addressing 4096/8192 memory locations. Am I reading the chart wrong?
Dala word4 bit 8 bit 16 bit 32 bit length 4096 (4K) 8192 (8K) Memory65,536 (64K) 32,768 (32K) adress range 65,536 (64K) 1,048,576 (IM) 2,097.152 (2M) *4,194,304 (4M) 4,294,967,296 (4G) 34,359,738,367 (32G) Word size and memory addressing range of some commonly available microprocessors.Explanation / Answer
The table is just depicting about word size and addressing range of some commonly available microprocessor.
The word length is given as 4bit with a memory 4096 blocks or words so total memory will be 4096 * 4 = 16384 bits
here you will not address all the bits , if you address all the bits you will need 14bits for words you just need 12 bits,similarly for rest of the cases
Still any doubt you can comment!
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