Define a function sort which accepts only a numeric comparison predicate and a l

Q: Define a function sort which accepts only a numeric comparison predicate and a l

sorting.py def sort(sign, alist): if sign == '': return sorted(alist, reverse = True) print(sort('', (1, 2, 3, 6, 4)))

ID: 3864594 • Letter: D

Question

Define a function sort which accepts only a numeric comparison predicate and a list of numbers as arguments, in that order, and returns the list of numbers sorted by the predicate. Follow Design Guidelines Four, Five, and Six completely. A > (sort (sort '(3)) 5 (3) 6 7 > (sort (sort (sort (sort > '()) 17 () 18 19 > (sort > '(1)) 20 (1) 21 22 > (sort > '(1 2)) 23 (2 1) 24 25 > (sort > '(1 2 3)) 26 (3 2 1) 27 28 > (sort > '(1 2 3 4 5 6 7 8 9)) 29 (9 8 7 6 5 4 3 2 1)

Explanation / Answer

sorting.py

def sort(sign, alist):
if sign == '<':
return sorted(alist)
elif sign == '>':
return sorted(alist, reverse = True)

print(sort('<', (1, 2, 3, 6, 4)))

print(sort('>', (1, 2, 3, 6, 4)))

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Define a function sort which accepts only a numeric comparison predicate and a l

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