1. If a relational database table is in the third normal form, it is also in a.
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Question
1. If a relational database table is in the third normal form, it is also in
a. the first normal form.
b. the second normal form.
c. the Boyce-Codd normal form.
d. both a. and b.
2. ______________________ guarantee(s) the access structure is always balanced when a lot of updates such as insertions and deletions of file records occur.
a. Multi-Way search tree
b. Dynamic hashing
c. B-tree/B+-tree
d. Multilevel index
3. Please indicate what the highest normal form is for the given relation schema R(A, B, C, D), the key for the schema: AB, and the set of functional dependencies, AB -> C, AB -> D.
a. The first normal form (1NF)
b. The second normal form (2NF)
c. The third normal form (3NF)
d. The Boyce-Codd normal form (BCNF)
4. If there is a one-to-many relationship between entity A and B, then
a. there exists a functional dependency from the primary key in A to the primary key in B, i.e.,
PK(A) ? PK(B).
b. there exists a functional dependency from the primary key in B to the primary key in A, i.e.,
PK(B) ? PK(A).
c. both a. and b.
d. neither a. nor b.
5. A database language consists of
a. data definition language
b. data manipulation language
c. both a. and b.
d. neither a. nor b.
Explanation / Answer
1.answer: d
Explanation:
first normal form: attribute values are atomic and nested relations not allowed,multivalued attributes not allow
Second normal form:non key attribute is fully depend on key attribute.
if there is any partial dependencies exist remove it.
Third normal from :if there is any transitive dependecies are exists remove it.
BCNF more strict than 3NF.
a relation is in BCNF it already in 1NF,2NF,3NF.
a relation is in 3NF it is in 1NF ,2NF, but not in BCNF.
2.answer: c
B/B+ Trees are dynamic indexing techniques they balance the tree and provide guarantte to access very fastly.
and keeping all the nodes at same distance.
3.answer: b
given ralation is in 2NF nonkey fully depend on key attribute.(C& D are non keys depend on key AB)
It not in 3NF because C is not part of key or D is not part of key hence the Relation is in 2NF
in 3NF FD: X->Y If either x is primary key or Y is part of key.
4.answer: c
5.answer:C
Explanation:
data definition language: to specify the various data base schemas and their attributes and their domains. by using the following commands. create ,alter ,drop, truncate the tables
data manipulation language:to perform various data manipulations like
retrival of data stored in database,inserting information into database, deletion of information from the database and modification of data.
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