Python 3.0=< Now you need to implement a function called code_block (word, key)

Question

Python 3.0=<

Now you need to implement a function called code_block (word, key) that takes an 8-letter word and an 8-digit key as parameters and encrypt each letter of the word with the corresponding digit of the key. The function code_block must call the function code_char that you have implemented in question 1.

>>> code_block(’abcdefgh’,’12121212’)

’bddffhhj’

>>>code_block(’xxyyxxaa’,’44556677’)

'bbddddhh'

• You will need to use the string concatenation operator + for joining up strings.

>>> 'a'+'b' 'ab'

• The key used to encrypt the message is a string so you will need the builtin function int to convert an ASCII digit into its corresponding number

>>> int('4')

4

code char=  

def code_char(c,key):
if ((ord(c)>=97) and (ord(c)<=122)):
result= (ord(c) + key - ord('a'))%26
return chr(ord('a') + result)
elif ((ord(c)>= 65) and (ord(c) <= 90)):
result= (ord(c) + key - ord('A'))%26
return chr(ord('A') + result)
else:
print ("invalid input")

Explanation / Answer

def code_block(word,key):

encrypted_word = ""#take zero character string initially

   for (w,k) in zip(word,key):# iterate each character from word and key
       encypted_word = encrypted_word + code_char(w,int(k))#calling and appeding each encrypted character
   return encrypted_word#returning final encrypted string

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