this is my c code. i created 2 child processes. but i do not know how to solve b

Question

this is my c code.

i created 2 child processes.

but i do not know how to solve below requirements...

can you add some codes for me? thanks

1. Make any of the variables of a parent share with any of its child processes

2. Make the children of the same parent share some variables between themselves

int main()
{
int fd;
pid_t pid;

pid = fork();

if (pid < 0)
{
  fprintf(stderr, "Error");
  exit(EXIT_FAILURE);
}

//child 1
else if (pid == 0)
{
  printf("I am child 1. ");
}
else
{
  pid = fork();

  // child 2
  if (pid == 0)
  {
   printf("I am child 2. ");  
  }
  else
  {

   wait (NULL);
   exit(EXIT_SUCCESS);
  }
}
}

Explanation / Answer

#include<stdio.h>
#include<stdlib.h>
int main()
{
int fd;
pid_t pid;

int share = 0;
pid = fork();
// from here onwards if fork is successfull ..system make two identical copies of address spaces
//both processes (parent and child) will start executing after fork() statement..
//they now share the same varaible,share
if (pid < 0)
{
fprintf(stderr, "Error");
exit(EXIT_FAILURE);
}

//child 1
else if (pid == 0)
{
printf("I am child 1. ");
share++;

printf("pid : %d ,share :%d ",getpid(),share);//shows which process is printing it..
//we can't expect a particular order here...
//both access printf buffer at same time//


}
else
{
pid = fork();

// child 2
//here child 2 ,child 1 and parent also sharing the same variable..
//because another identical address space is created for parent again..

if (pid == 0)
{
   printf("I am child 2. ");
   printf("pid : %d ,share :%d ",getpid(),share);//shows which process is printing it..
//we can't expect a particular order here...
//both access printf buffer at same time//
  
}
else
{

   wait (NULL);
   exit(EXIT_SUCCESS);
}
}
}

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