import os number = [] count = 0 sum = 0 fName =input(\"Enter the file name: \")

Question

import os

number = []

count = 0

sum = 0

fName =input("Enter the file name: ")

if os.path.exists(fName):

with open(fName, 'rb') as f:

try:

for line in f:

number.append(int(line))

count = count + 1

except :

print("Unable to open file: " + str(fName))

# start calculation sum,avg, max,min

i = 0

min = number[0];

max = number[0];

while i < count:

# find min

if(min > number[i]):

min = number[i]

# find max

if (max < number[i]):

max = number[i]

# calc avg

sum += number[i]

i = i + 1

avg = float(sum / count)

print('File name:' + fName)

print("Sum:" + str(sum))

print("Count:" + str(count))

print("Average:" + str(avg))

print("Maximum:" + str(max))

print("Minimum:" + str(min))

print("Range:" + str((max - min)))

Output it says

Enter the file name

If I enter djasf242 it just comes up

min = number[0];

IndexError: list index out of range

>>>

I want it to say No such file exists try again.

and it repeats the program. How do you get the program to do that.

Explanation / Answer

The answer is as follows:

As per my understanding the expectation is that till the user gives a correct filename the program should loop
asking for correct filename.

The code modification is as follows:

fName =input("Enter the file name: ")
valid = 0
while valid == 0:
    if os.path.exists(fName):
       valid = 1
    else:
       print("No such file exists try again")
       fName =input("Enter the file name: ")

with open(fName, 'rb') as f:
   for line in f:
   number.append(int(line))
   count = count + 1

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