Demonstrate fixed point numbers and arithmetic in C programming language. The nu

Question

Demonstrate fixed point numbers and arithmetic in C programming language.

The number of bits assigned to the integer and fractional parts of a fixed point representation are fixed by convention.
Fixed point numbers are an integral data type and hence can be processed faster by a computer than with other fractional floating point representations.
Fixed point numbers are converted to a string by casting the number to a int32_t data type, dividing by a float number of fractional values, and outputting the result using the floating point specifier (ie. %f) followed by the number of fractional bits.

Example:

The output is:

Explanation / Answer

Hi,

Please find below the sample code in C for fixed pointer arithmetic-

#include <stdio.h>

typedef short int16;

typedef int int32;

int main( void )

{

    int16 a;

    int16 b;

    int16 c;

    int32 d;

    printf("example 1: magnitude of divisor is greater than magnitude of dividend ");

    a = 0x0400;

    b = 0x2000;

    if ( abs(b) > abs(a) ) {

        c = (int16)(((int32)a << 15) / ((int32)b));

    } else {

        printf("division error ");

    }

    printf("a = %d, b = %d, c = %d ",a,b,c);

    printf("a = 0x%x, b = 0x%x, c = 0x%x ",a,b,c);

    // example 2: no restrictions on divisor other than not 0

    printf(" example 2: no restrictions on divisor other than not 0 ");

    a = 0x7fff;

    b = 0x0001;

    if ( b != 0 ) {

        d = ((int32)a << 15) / ((int32)b);

    } else {

        printf("division by zero error ");

    }

    printf("a = %d, b = %d, d = %d ",a,b,d);

    printf("a = 0x%x, b = 0x%x, d = 0x%x ",a,b,d);

   return 0;

}

Regards,

Vinay Singh

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