Processor A has a CPI 1.2 and a clock rate of 1 GHz. Processor B has a CPI of 2.

Question

Processor A has a CPI 1.2 and a clock rate of 1 GHz. Processor B has a CPI of 2.0 and a clock rate of 2 GHz. Processor C has a dock rate of 2.5 GHz (400 ps/cycle) and a CPI of 2.6. All three processors implement the same instruction set. Determine the time per instruction for each processor and write it in the correct spot. Which processor is faster? How many times faster is it than the slowest processor? Show your work! Processor A time per instruction___ Processor B time per instruction____ Processor C time per instruction ____ Which is fastest? How many times faster than the slowest?

Explanation / Answer

CPU Time = seconds/program = instructions/program * cycles/instruction * second/cycle

T = I * CPI * C

and

GHz = 109 Hz; Second = 109 nanosecond

Processor A time per instruction = CPI * C = 1.2 * 10-9 = 1.2 nanoseconds

Processor B time per instruction = CPI * C = 2 / 2 * 109 = 1 nanoseconds

Processor C time per instruction = CPI * C = 2.6 / 2.5 * 109 = 1.04 nanoseconds

Processor A is faster.

Processor B is slowest.

Processor A is 1.2 times faster than the slowest.

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