1. String Utilities In this exercise you will implement several utility function

Question

1. String Utilities

In this exercise you will implement several utility functions involving strings. You will place all of your function prototypes in a header file named string utils.h and all of your function definitions in a source file named string utils.c.

You should implement your own main test driver program to test your functions, but you need not hand it in.

a. void addChar(char *str, char c, int n)

- this function should add a char c at index n in string str.
The following characters should be shifted up to make room for the inserted character.

For example, a call to this function on the string “Hello World”, ‘p’, ‘4’, would result in the string “Hellpo World”

b. int numChar(const char *src, char c)
- this example determines the number of character c appears in the string. It does not

matter if the letter in the string is capitalized or not.
For example, a call to this function on the string “HellO World”, ‘o’, would return 2.

c. int isPalindrome(const char *src)
- this example determines if the string src is a palindrome or not. Return 1 if the string

is a palindrome and 0 if not.
For example, a call to this function on the string “testset”, will return 1

d. int strCompare(const char *str, const char *str2)

- Write your own string comparison function that compares two strings for equality. You cannot use the < string.h > string comparison functions. Make sure the compare function is case insensitive. Return 0 if the two strings are equal and 1 if they are not.

For example, a call to this function on the string “Hello world”, and “Hello World” will return 0.

e. char* strCat(char *str, char *str2)

- Concatenate the two strings “str” and “str2” and store that in a newly created dynamic string. The function should return this dynamic string. You cannot use the < string.h > concatenation functions.

For example, a call to this function on the string “Hello”, and “ World” will return a dynamically created string that contains “Hello World”.

f. void consonantVowel(char *str)
- This function will print out the number of consonants and vowels in the string. Note:

printing should be done in the function (notice the return type is void).

For example, a call to this function on the string “Hello”, will print Consonants: 3, Vowels 2.

Explanation / Answer

b.)

int numChar(const char *src, char c)
{int i,count=0;
for(i=0;i<strlen(src);i++)
{
if(src[i]==c)
count++;
}
return count;

}

c)

int isPalindrome(const char *src)
{
  
int l = 0;
int h = strlen(src) - 1;

while (h > l)
{
if (src[l++] != src[h--])
{
  
return 0;
}
}
return 1;
}

d.
int strCompare(const char *str, const char *str2)
{
  
int c = 0;

while (str[c] == str2[c]) {
if (str[c] == '' || str2[c] == '')
break;
c++;
}

if (str[c] == '' && str2[c] == '')
return 0;
else
return -1;
}

e.

char* strCat(char *str, char *str2)
{
const size_t len1 = strlen(str);
const size_t len2 = strlen(str2);
char *result = malloc(len1+len2+1);
memcpy(result, str, len1);
memcpy(result+len1, str2, len2+1);
return result;
}

f.

void consonantVowel(char *str)
{
int consonant=0,vowel=0,i;
for(i=0; i<strlen(str); i++)
{
switch(str[i])
{
case 'a':
case 'e':
case 'i':
case 'o':
case 'u':
case 'A':
case 'E':
case 'I':
case 'O':
case 'U':
vowel++;
break;
default:
if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))
{
consonant++;
}
}
}

  
printf("consonant: %d ", consonant);
printf(" vowel:%d ", vowel);
}

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