This question deals with palindromic dates-that is, dates that read the same for

Question

This question deals with palindromic dates-that is, dates that read the same forward and backward. The year 2002 was a palindromic year. When is the next palindromic year? If dates are written MMDDYYYY, then May 2, 2050, is a palindromic date. What is the earliest palindromic date of the 21st century? Create a program that identifies all palindromic dates in a given year. First a user enters a year. Then the program reports the palindromic dates. Finally, the program asks the user if he or she wishes to try again. Note that you need a Palindrome class that permits testing "digit" characters.

Explanation / Answer

Answer for the given Palindrom Question:

As given in problem statement implemented with the help of class Palindrom and functions with user choice

#include <iostream>
using namespace std;

class Palindrome
{
   int year;
public:
   Palindrome()
   {
       year = 0;
   }
   Palindrome(int year1)
   {
       year = year1;
   }
   void PalindromeYear(int num)
   {
       int n, digit, rev = 0;
       //cout << "Enter a year: "<<endl;
       //cin >> num;
       n = num;

       do
       {
           digit = num % 10;
           rev = (rev * 10) + digit;
           num = num / 10;
       } while (num != 0);

       cout << " The reverse of the number is: " << rev << endl;

       if (n == rev)
           cout << " The Year is a palindrome year";
       else
           cout << " The year is not a palindrome year";

   }
};
int main()
{
Palindrome pal;
   char ch;
   int year2;
   do{
       cout<<"Enter Year :"<<endl;
       cin>>year2;
   pal.PalindromeYear(year2);
   cout<<"Do you want try one more time enter y or n"<<endl;
   cin>>ch;
   }while(ch == 'y' || ch == 'Y');
return 0;
}

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