Exercise 6: The assembly of a product consists of eight tasks as given below. Th
ID: 384984 • Letter: E
Question
Exercise 6: The assembly of a product consists of eight tasks as given below. The company works 5 days per week in two shifts every day. Each shift is 9 hours and workers have 30 minute meal-break and two 15-minute tea breaks. The desired production rate is 1500 units/week. TaskTime (seconds)Immediate Predecessors 90 90 30 50 20 25 30 70 4 5,6 a) Calculate the maximum cycle time to achieve the desired production rate b) Draw the precedence diagram. c) Assign tasks to stations using the Ranked Positional Weight (RPW) technique assuming a cycle time of 150 seconds. d) Calculate the balance delayExplanation / Answer
Total available time per shift
= 9 hours – 30 minutes meal break – 2 x 15 minutes = 9 hours – 60 minutes = 8 hours
Thus total available time per day with 2 shifts = 8 x 2 = 16 hours
Total available time in 5 days = 16 x 5 = 80 hours = 80 x 3600 seconds
Desired production rate = 1500 units/ week
Thus Maximum cycle time = 80 x 3600 / 1500 = 192 seconds
MAXIMUM CYCLE TIME TO ACHIEVE DESIRED PRODUCTION RATE = 192 SECONDS
The Precedence diagram as follows :
1
2
3
4
5
6
7
8
Following Steps are involved in Ranked Positional Weight (RPW ) method.
Step 1: Draw the precedence diagram
Step 2: For each work element, determine the positional weight. It is the total time on the longest path from the beginning of operation to the last operation of the network.
Step 3: Rank the work elements in descending order of ranked positional weight (R.P.W)
Step 4: Assign the work element to a station. Choose the highest RPW element. Then, select the next one. Continue till cycle time is not violated. Follow the precedence constraints also. Since cycle time is 150 seconds , total duration of any workstation shall not exceed 150 seconds
Step 5: Repeat step 4 till all operations are allotted to one station.
Accordingly , total duration of each path as per following :
Path 1-3-6-7-8 = 90 + 30 + 25 + 30 + 70 = 245 seconds
Path 1-4-6-7-8 = 90 + 50 + 25 + 30 + 70 = 265 seconds
Path 2 – 5- 7 -8 = 90 + 20 + 30 + 70 = 210 seconds
From above, since activity 1 has higher RPW than 2 , we will start with 1. After starting with activity 1, we should choose activity 4 ( over activity 3 ) since 4-6-7-8 will have higher RPW over 3-6-7-8
Workstation
Activity
Total duration ( seconds)
Balance delay = 150 seconds – Total duration
1
1, 4
90 + 50 = 140
150 – 140 = 10
2
2, 5 , 7
90 + 20 + 30 = 140
150 – 140 = 10
3
3,6
30 + 25 = 55
150 – 55 = 95
8
70
150 – 70 = 80
Thus , Cumulative balance delay for all workstations = 10 + 10 + 95 + 80 seconds = 195 seconds
MAXIMUM CYCLE TIME TO ACHIEVE DESIRED PRODUCTION RATE = 192 SECONDS
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