You are asked to find the angle between the minute hand and the hour hand on a r

Question

You are asked to find the angle between the minute hand and the hour hand on a regular analog clock. Assume that the second hand, if there were one, would be pointing straight up at the 12. Give all angles as the smallest positive angles. For example 9: 00 is 90 degrees: not -90 or 270 degrees. Input: The input is a list of times in the form H: M, each on their own line, with 1 lessthanorequalto H lessthanorequalto 12 and 00 lessthanorequalto M lessthanorequalto 59. The input is terminated with the time '0: 00'. Note that H may be represented with 1 or 2 digits (for 1-9 or 10-12, respectively): M is always represented with 2 digits (the input times are what you typically see on a digital clock). Output: The output displays the smallest positive angle in degrees between the hands for each time. The answer should between 0 degrees and 180 degrees for all input times. Display each angle on a line by itself in die same order as the input. The output should be rounded to the nearest 1/1000, i.e., three places after the decimal point should be printed.

Explanation / Answer

Solution:-

The below given C code calculates angle between hour hand and minute hand of an analog watch. The function calculates calcAngle calculates the angle. A driver program also there to test the program.

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// Calculate angle between hour and minute hand of an // analog watch

#include <stdio.h>

#include <stdlib.h>

// function to find minimum of two integers

int min(int x, int y) { return (x < y)? x: y; }

int calcAngle(double h, double m)

{

    // Input validation

    if (h <0 || m < 0 || h >12 || m > 60)

        printf("Wrong input");

    if (h == 12) h = 0;

    if (m == 60) m = 0;

    // Calculating angles of hour and minute hands

    // with reference to 12:00

    int hour_angle = 0.5 * (h*60 + m);

    int minute_angle = 6*m;

    // Find the difference between two angles

    int angle = abs(hour_angle - minute_angle);

    // Return the smaller angle of two possible angles

    angle = min(360-angle, angle);

    return angle;

}

// Driver program to test above function

int main()

{

    printf("%d ", calcAngle(9, 60));

    printf("%d ", calcAngle(3, 30));

    return 0;

}

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