Write a program named Symmetry.java, within this class, define a method symmetri

Question

Write a program named Symmetry.java, within this class, define a method

symmetricNumber method that accepts an integer n as a parameter and prints

a symmetric sequence of n numbers with descending integers ending in 1 followed by

ascending integers beginning with 1, as in the table below:

Call Output

symmetricNumber(1); 1

symmetricNumber(2); 1 1

symmetricNumber(3); 2 1 2

symmetricNumber(4); 2 1 1 2

symmetricNumber(5); 3 2 1 2 3

symmetricNumber(6); 3 2 1 1 2 3

symmetricNumber(7); 4 3 2 1 2 3 4

symmetricNumber(8); 4 3 2 1 1 2 3 4

symmetricNumber(9); 5 4 3 2 1 2 3 4 5

symmetricNumber(10); 5 4 3 2 1 1 2 3 4 5

Notice that for odd numbers the sequence has a single 1 in the middle while for even values

it has two 1s in the middle. Include main method in this class and test your method with the following calls:

symmetricNumber(1)

symmetricNumber(2)

symmetricNumber(5)

symmetricNumber(6)

symmetricNumber(9)

symmetricNumber(10)

symmetricNumber(12)

Explanation / Answer

The program with class Symmetry, which define a method called symmetricNumber method that accepts an integer n as a parameter and prints a symmetric sequence of n numbers with descending integers ending in 1 followed by ascending integers beginning with 1.the java programming code

for odd numbers the sequence has a single 1 in the middle while for even values it has two 1s in the middle. it Includes main method in this class and test method with the following calls:

symmetricNumber(1)

symmetricNumber(2)

symmetricNumber(5)

symmetricNumber(6)

symmetricNumber(9)

symmetricNumber(10)

symmetricNumber(12) is the java programming code is:

public class Symmetry
{

   public static void symmetricNumber(int n) {

   if( n < 1 )
   throw new IllegalArgumentException();

   if( n == 1 ) {
   System.out.println("1");

   } else if( n == 2 ) {
   System.out.println("1 1");

   } else if( n % 2 == 0 ){
   System.out.print((n / 2) + " ");
   symmetricNumber(n - 2);
   System.out.println(" " + (n / 2));

   } else if( n % 2 == 1 ) {
   System.out.print(((n + 1) / 2) + " ");
   symmetricNumber((n - 2));
   System.out.println(" " + ((n + 1) / 2));
   }   
   }
   public static void main(String []args)
   {
       Symmetry s=new Symmetry();
       s.symmetricNumber(1);
       s.symmetricNumber(2);
       s.symmetricNumber(5);
       s.symmetricNumber(6);
       s.symmetricNumber(9);
       s.symmetricNumber(10);
       s.symmetricNumber(12);
         
}
}

the sample output is:

1
1 1
3 2 1
2
3
3 2 1 1
2
3
5 4 3 2 1
2
3
4
5
5 4 3 2 1 1
2
3
4
5
6 5 4 3 2 1 1
2
3
4
5
6

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