Create a program that generates a simple day schedule with 3 activities, based u
ID: 3848376 • Letter: C
Question
Create a program that generates a simple day schedule with 3 activities, based upon the following inputs:
1-Activity Name (Keep it to a short word if you are using tabs, or in the length range using a .format() or .printf() statement)
2-Activity Starting Hour (in military time, which is a 24 hr clock, acceptable numbers 1-24 – do data validation)
3-Activity Ending Hour (in military time also) – perform a validity check to be sure that this number is greater than or equal to Starting Hour
4-Hints:
.Activities do not have to be entered in chronological order, but there should be no overlapping. Start/End numbers are inclusive.
.Utilize a nested loop, the outer loop goes from 1..24 for the hour of day.
.For each iteration of the outer loop, have an inner for() loop that goes from col=1 to col=3
.Use a switch statement to test for the case of 1, 2, and 3 to represent each of 3 cols/activities. Then, under the case, use an if statement to test if the hour falls between the start/end time for this activity. Then perform the output of the activity into the appropriate column (tabs work here, or you can use the .printf() or .format() method, which is preferred. If using tabs, you can tab out when processing activity 1 - two tabs, activity 2 - three tabs, and activity 3 - four tabs, for example.
.Perform data validation to prevent bad input.
.This program requires at least 3 variables for each of the 3 activities you are logging, and 2 loop counter variables.
.Arrays are not necessary, but if you want to use them you may.
Sample Output:
Enter activity 1 name: Eat
Enter activity 1 starting hour: 12
Enter activity 1 ending hour: 14
Enter activity 2 name: Sleep
Enter activity 2 starting hour: 1
Enter activity 2 ending hour: 9
Enter activity 3 name: School
Enter activity 3 starting hour: 16
Enter activity 3 ending hour: 22
My Schedule
Hour Act1 Act2 Act3
1 Sleep
2 Sleep
3 Sleep
4 Sleep
5 Sleep
6 Sleep
7 Sleep
8 Sleep
9 Sleep
10
11
12 Eat
13 Eat
14 Eat
15
16 School
17 School
18 School
19 School
20 School
21 School
22 School
23
24
Explanation / Answer
Code:
#include <stdio.h>
#include <stdlib.h>
/*
program to generate simple schedule for 24 hours
program name: schedule.c
*/
/* function prototype */
void validate(int, int);
int main()
{
/* declaring variables */
char act1[30], act2[30], act3[30];
int act1_start, act1_end, act2_start, act2_end, act3_start, act3_end;
int col, hour;
/* getting activity and starting, ending hour information from the user */
printf(" Enter activitiy 1 name: ");
scanf("%s", act1);
printf(" Enter activity 1 starting hour: ");
scanf("%d", &act1_start);
printf(" Enter activity 1 ending hour: ");
scanf("%d", &act1_end);
validate(act1_start, act1_end);
printf(" Enter activitiy 2 name: ");
scanf("%s", act2);
printf(" Enter activity 2 starting hour: ");
scanf("%d", &act2_start);
printf(" Enter activity 2 ending hour: ");
scanf("%d", &act2_end);
validate(act2_start, act2_end);
printf(" Enter activitiy 3 name: ");
scanf("%s", act3);
printf(" Enter activity 3 starting hour: ");
scanf("%d", &act3_start);
printf(" Enter activity 3 ending hour: ");
scanf("%d", &act3_end);
validate(act3_start, act3_end);
/* printing the schedule */
printf(" My Schedule ");
printf(" Hour Act1 Act2 Act3");
for(hour = 1; hour <= 24; hour++){
printf(" %d", hour);
for(col = 1; col <= 3; col++){
/* checking if the hour falls below any of the activities */
switch(col){
case 1:
if(hour >= act1_start && hour <= act1_end) printf(" %s", act1);
break;
case 2:
if(hour >= act2_start && hour <= act2_end) printf(" %s", act2);
break;
case 3:
if (hour >= act3_start && hour <= act3_end) printf(" %s", act3);
break;
}
}
}
printf(" ");
return 0;
}
/* function to validate if the start and end hours are <=24 and start date less than end date */
void validate(int a, int b)
{
/* checking if start and end hours are >= 1 and <= 24 */
if( a >= 1 && a <= 24 && b >= 1 && b <= 24){
/* checking if ending hour is less than starting hour */
if(b < a){
printf(" End hour should be more than start hour ");
exit(1);
}
}
else{
printf(" start and end hours should be from 1-24 hours ");
exit(1);
}
}
Execution and output:
Unix Terminal> ./a.out
Enter activitiy 1 name: Eat
Enter activity 1 starting hour: 12
Enter activity 1 ending hour: 14
Enter activitiy 2 name: Sleep
Enter activity 2 starting hour: 1
Enter activity 2 ending hour: 9
Enter activitiy 3 name: School
Enter activity 3 starting hour: 16
Enter activity 3 ending hour: 22
My Schedule
Hour Act1 Act2 Act3
1 Sleep
2 Sleep
3 Sleep
4 Sleep
5 Sleep
6 Sleep
7 Sleep
8 Sleep
9 Sleep
10
11
12 Eat
13 Eat
14 Eat
15
16 School
17 School
18 School
19 School
20 School
21 School
22 School
23
24
Unix Terminal> ./a.out
Enter activitiy 1 name: Eat
Enter activity 1 starting hour: 10
Enter activity 1 ending hour: 9
End hour should be more than start hour
Unix Terminal> ./a.out
Enter activitiy 1 name: Sleep
Enter activity 1 starting hour: 20
Enter activity 1 ending hour: 24
Enter activitiy 2 name: Eat
Enter activity 2 starting hour: 11
Enter activity 2 ending hour: 14
Enter activitiy 3 name: Run
Enter activity 3 starting hour: 6
Enter activity 3 ending hour: 4
End hour should be more than start hour
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