This is in rogramming language C Write a program that takes as input four dates

Question

This is in rogramming language C

Write a program that takes as input four dates in the format MM:dd:yyyy and prints them out in a tabular format, as shown below (items underlined are to be entered by the user): The year, month and day columns should be separated by tabs ( ) (this also refers to the words Year, Month and Day from the header of the table). The year column should occupy 4 spaces and the values should be right justified. The month column should occupy 2 spaces and the values should be right justified. The day column should occupy 2 spaces and the values should be left justified. Save your program in a file called date.c. Modify your previous program so that if the value of the year is less than 4 digits, add 0 in front of the year to make the year has 4 digits. If the values of month and day are less than 10 (meaning they have just one digit), the values of month/day will always have two digits displayed (as shown below): Save your program in a file called date c.c.

Explanation / Answer

//Problem1:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define MAX 100
int main()
{
   char date_str[12];
   char str[5];
   char c1, c2, c3;
   struct date
   {
       char year[5];
       char month[3];
       char day[3];
   } Date[MAX];
   int count = 0,i,j =0,k = 0 ;
   //take user input till user enters 0 to quit
  
   do
   {
       printf("Enter date %d (MM/dd/yyyy) : ", count+1);
       scanf("%s", date_str);
       if (strcmp(date_str, "0") == 0)
           break;
       i = 0;
       k = 0;
       j = 0;
       while (date_str[i] != '')
       {
           if (date_str[i] != '/')
               str[j++] = date_str[i++];
           else
           {
               switch (k)
               {
               case 0:
                   str[j] = '';
                   strcpy(Date[count].month ,str);
                   i++;
                   j = 0;
                   k++;
                   break;
               case 1:
                   str[j] = '';
                   strcpy(Date[count].day, str);
                   i++;
                   j = 0;
                   k++;
                   break;
              
               }
           }
          
       }
       str[j] = '';
       strcpy(Date[count].year, str);
       count++;
   } while (strcmp(date_str, "0") != 0);
   //now display the date in tabular form
   printf("---------------------------------------------------------------------------- ");
   printf("Year   Month   Day ");
  
   for (i = 0; i < count; i++)
   {
       printf("%4s %2s %2s ", Date[i].year, Date[i].month, Date[i].day);
   }
}

---------------------------------------------

//output problem1

Enter date 1 (MM/dd/yyyy) : 5/3/2017
Enter date 2 (MM/dd/yyyy) : 2/13/2010
Enter date 3 (MM/dd/yyyy) : 7/4/1776
Enter date 4 (MM/dd/yyyy) : 11/13/200
Enter date 5 (MM/dd/yyyy) : 0
----------------------------------------------------------------------------
Year Month Day
2017 5 3
2010 2 13
1776 7 4
200 11 13

-------------------------------

//problem2

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define MAX 100
int main()
{
   char date_str[12],str1[5],str2[3],str3[3];
   char str[5];
   char c1, c2, c3;
   struct date
   {
       char year[5];
       char month[3];
       char day[3];
   } Date[MAX];
   int count = 0,i,j =0,k = 0 ;
   //take user input till user enters 0 to quit
  
   do
   {
       printf("Enter date %d (MM/dd/yyyy) : ", count+1);
       scanf("%s", date_str);
       if (strcmp(date_str, "0") == 0)
           break;
       i = 0;
       k = 0;
       j = 0;
       while (date_str[i] != '')
       {
           if (date_str[i] != '/')
               str[j++] = date_str[i++];
           else
           {
               switch (k)
               {
               case 0:
                   str[j] = '';
                   strcpy(Date[count].month ,str);
                   i++;
                   j = 0;
                   k++;
                   break;
               case 1:
                   str[j] = '';
                   strcpy(Date[count].day, str);
                   i++;
                   j = 0;
                   k++;
                   break;
              
               }
           }
          
       }
       str[j] = '';
       strcpy(Date[count].year, str);
       count++;
   } while (strcmp(date_str, "0") != 0);
   //now display the date in tabular form
   printf("---------------------------------------------------------------------------- ");
   printf("Year   Month   Day ");
  
   for (i = 0; i < count; i++)
   {
       strcpy(str1, Date[i].year);
       strcpy(str2, Date[i].month);
       strcpy(str3, Date[i].day);
       if (strlen(Date[i].year) < 4)
       {
           strcpy(str1, "0");
           strcat(str1, Date[i].year);
       }
       if (strlen(Date[i].month) < 2)
       {
           strcpy(str2, "0");
           strcat(str2, Date[i].month);
       }
       if (strlen(Date[i].day) < 2)
       {
           strcpy(str3, "0");
           strcat(str3, Date[i].day);
       }
       printf("%4s %2s %2s ", str1, str2, str3);
   }
}

-----------------------------------------------------------

//output problem2

Enter date 1 (MM/dd/yyyy) : 5/3/2017
Enter date 2 (MM/dd/yyyy) : 2/13/2010
Enter date 3 (MM/dd/yyyy) : 7/4/1776
Enter date 4 (MM/dd/yyyy) : 11/13/200
Enter date 5 (MM/dd/yyyy) : 0
-----------------------------------------------------------------------
Year Month Day
2017 05 03
2010 02 13
1776 07 04
0200 11 13

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