C++ Please!! The following program is the base for the game: tic-tac-toe. The ma
ID: 3843386 • Letter: C
Question
C++ Please!!
The following program is the base for the game: tic-tac-toe. The main function and program structure is given, don’t modify them. Complete three functions as required. Compile and run this program, and then you can play the game. Have fun!
#include<iostream> using namespace std;
const int DIM=3;
char chessboard[DIM][DIM]; //initChessBoard
void initChessBoard(char cb[][DIM])
{
//set all the elements of the ChessBoard to blanks
//Complete this part in the following:
}
//printChessBoard
void printChessBoard(char cb[][DIM])
{
//print all the elements of the chessBoard with each row in one line
//Complete this part in the following:
}
//putChequer
bool putChequer(char cb[][DIM], int i, int j, char x)
{
/* if i and j are not out of bound(that is, i and j are in the range of 0 and DIM-1) and cb[i][j] is not occupied(that is, the value of cb[i][j] is blank), set cb[i][j] to be the value of x and return true. Otherwise, return false.*/
// Complete this part in the following:
}
//judge the state of the game. The player has put x in the position (row, col).
// If all the elements in this row are x, x wins
// If all the elements in this column are x, x wins.
// If x is in the main diagonal, and if all the elements in the main diagonal are x, x wins.
// If x is in the opposite diagonal, and if all the elements in the opposite diagonal are x, x wins.
bool state(char cb[][DIM], int row, int col, char x)
{
/* We declare four variables count1, count2, count3, count4 to represent the occurrence number of x in row number row, column number col, in the main diagonal, and in the opposite diagonal. If after calculation, count1, count2, count3 or count4 equals to DIM, return true(that is, x wins). */
int count1=0, count2=0, count3=0, count4=0;
for(int i=0; i<DIM; ++i)
{
// Complete this part in the following:
// if the element in position (row, i) is x, count1 is increased by 1. // if the element in position (i, col) is x, count2 is increased by 1.
/* if x is in the main diagonal, and the element in position (i, i) is x, count3 is increased by 1.*/
/* if x is in the opposite diagonal, and the element in position (i, DIM-1-I) is x, count4 is increased by 1.*/
}
return (count1==DIM || count2==DIM || count3==DIM || count4==DIM);
}
int main()
{
int row, col;
int blanks=DIM*DIM;
initChessBoard(chessboard);
printChessBoard(chessboard);
char cur='O';
cout<<"Input the position(row col), (-1 -1) for exit; It is the turn of "<<cur<<endl;
cin>>row>>col;
while(row!=-1 && col!=-1)
{
if(!putChequer(chessboard, row, col, cur))
{
cout<<"Invalid move"<<endl;
printChessBoard(chessboard);
}
else
{
--blanks;
printChessBoard(chessboard);
if(state(chessboard, row, col, cur))
{
cout<< cur << " Wins"<<endl;
return 0;
}
}; if(blanks==0)
{
cout<< "Ties"<<endl;
return 0;
}
if(cur=='X')
cur= 'O';
else cur='X';
}
cout<<"Input the position(row col), (-1 -1) for exit; It is the ture of "<<cur<<endl;
cin>>row>>col;
}
}
Explanation / Answer
CODE: #include using namespace std; const int DIM=3; char chessboard[DIM][DIM]; void initChessBoard(char cb[][DIM]); void printChessBoard(char cb[][DIM]); bool putChequer(char cb[][DIM], int i, int j, char x); bool state(char cb[][DIM], int row, int col, char x); int main() { int row, col; int blanks=DIM*DIM; initChessBoard(chessboard); printChessBoard(chessboard); char cur='O'; coutRelated Questions
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