1. (a) The Fibonacci numbers are the numbers in the following integer sequence,
ID: 3839224 • Letter: 1
Question
1. (a) The Fibonacci numbers are the numbers in the following integer sequence, called the Fibonacci sequence, and are characterised by the fact that every number after the first two is the sum of the two preceding ones: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 114, … etc. By definition, the first two numbers in the Fibonacci sequence are 0 and 1, and each subsequent number is the sum of the previous two. We define Fib(0)=0, Fib(1)=1, Fib(2)=1, Fib(3)=2, Fib(4)=3, etc. The first 22 Fibonacci numbers given below: Fib(0) Fib(1) Fib(2) Fib(3) Fib(4) Fib(5) Fib(6) Fib(7) Fib(8) Fib(9) Fib(10) 0 1 1 2 3 5 8 13 21 34 55 Fib(11) Fib(12) Fib(13) Fib(14) Fib(15) Fib(16) Fib(17) Fib(18) Fib(19) Fib(20) Fib(21) 89 144 233 377 610 987 1597 2584 4181 6765 10946 Write a MARIE program to calculate Fib(n), where the user inputs n. For example, if the user inputs 7, the program outputs the value 13; if the user inputs 15, the program outputs the value 610; if the user inputs 20, the program outputs the value 6765 etc. You need to write and run the program using MARIE simulator. Please include appropriate comments to make your code readable.[10 marks] (b) For some values of n, your program will not produce correct results. You can check this by gradually increasing the values of n and checking for the correct outputs. What is the maximum value of n for which your program produces a correct result? Why? Please comment on this [5 marks].
Explanation / Answer
public class Simple
{
public static void main(String a[])
{
int febCount = 15;
int[] feb = new int[febCount];
feb[0] = 0;
feb[1] = 1;
for(int k=2; k < febCount; k++)
{
feb[k] = feb[k-1] + feb[k-2];
}
for(int k=0; k< febCount; k++)
{
System.out.print(feb[k] + " ");
}
}
}
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