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Write a do-while loop that will iterate 1 time. You any not declare any variable

ID: 3835461 • Letter: W

Question

Write a do-while loop that will iterate 1 time. You any not declare any variables. J. Write an expression that determines the remainder when dividing z by x. Assume z and x are declared and initialized to a value. K. What is the C type of the following expression: size of (int)? Is it char, int, or double? L. Write an expression that shifts the value in variable x to the left by 3 bits. Assume x has been declared are assigned a value. M. Declare an array of 100 integers. N. Allocate an array of double values on the heap: the size of the array is held in a variable named size that is already declared. O. Given variables p and x, assign the address of x to p. You may assume the variables are declared and of the appropriate type. P. Assume that variable array is an integer array of length 101. Set the last element {greatest index) of array to 0. Q. Declare a variable and initialize it to hold the string

Explanation / Answer

Dear Student,

Here are the abswers...

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this loop print the statement one time only.

do

{

statement;

}while(0);      

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Answer : J

int z = 10;

int x = 3;

int remainder = z%x;

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Answer No: K

sizeof(int);           (for int type)

sizeof(float);           (for float type)

sizeof(double);        (for double type)

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Answer No: L

(3<<x)               will shift x to 3 bits left.

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Answer No: M

int arr[100];                    (array of 100 integer)

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Answer No: N

array = (double*)malloc(size   * sizeof(double));

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Answer No: Q

int x, *p;

p = &x;

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Answer No: P

int array[101];

array[100] = 0;               (set the last element to zero).

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Answer No: Q

char array[]   = "Good luck";

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Kindly Check and Verify Thanks...!!!

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