Linux Bash Create a logfile bash file that has the following data on each line o

Question

Linux Bash

Create a logfile bash file that has the following data on each line of the file (fields separated by |):
user name | process name | process time (in minutes)

eg:

smiths|Login|2
olivert|Login|2
northj|Login|2
denniss|Login|2
smithd|Login|2
smiths|Time Reporting|210
olivert|Payroll|155
northj|Server Maintenance|70
northj|Logfile Reporting|45
denniss|Report Printing|80
smithd|Payroll Program Updates|150
smithd|Benefit Program Updates|180
smiths|Logout|2
olivert|Logout|2
northj|Logout|2
denniss|Logout|2
smithd|Logout|2

Explanation / Answer

The below command prints the output in required format:

ps --no-heading -e -o uname,comm,etime | tr -s ' ' | tr '-' ' ' | tr ':' ' ' | awk '{ total=0; m=1; } { for (i=0; i < NF-2; i++) {total += $(NF-i)*m; m *= i >= 2 ? 24 : 60 }} {print $1,$2,total/60}' | tr ' ' '|'

**NOTE: The whole command is a single line.

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