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Java Homework help: Compress Sparse Array. Can someone help me with the followin

ID: 3831430 • Letter: J

Question

Java Homework help: Compress Sparse Array. Can someone help me with the following question?

/*

Please complete the following `SparseCompression` compression method to compress a sparse array.
**Assume that the sparse array only contains one non-zero integer and always starts with 0.**
Note: the input of the method is an `int[] array` and the output of the method is a `String`. (5 points)

For example:

input:

int[] array = {0, 0, 0, 0, 0, 0, 0, 999};

Output:
"#7, 999,"

input:

int[] array = {0, 0, 0, 1};

Output:
"#3, 1,"
  

*/
public class Compress
{
public static void main(String[] args)
{
int[] test = {0, 0, 0, 0, 0, 0, 0, 999};
String result = SparseCompression(test);

// expected result: "#7,999,"
System.out.println(result);
}

public static String SparseCompression(int[] array)
{
// Your code goes here
String result = "#6,3";
return result;
}
}

Explanation / Answer

public class Compress

{

   public static void main(String[] args)

   {

int[] test = {0, 0, 0, 0, 0, 0, 0, 999,0};

String result = SparseCompression(test);

// expected result: "#7,999,"

System.out.println(result);

   }

   public static String SparseCompression(int[] array)

   {

// Your code goes here

   int z=0;

   int len = array.length;

   int pos=0;

   for(int i=0;i<len;i++)

   {

       if(array[i]!=0)

       {

           pos=i;

           break;

       }

   }

String result = "#6,3";

result = "#"+(pos)+", "+array[pos]+",";

if(len-pos-1>0)

{

      result = result + " #"+(len-1-pos)+",";

}

return result;

   }

}

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