A polynomial is intersecting the x axis at - 4 and 2. Write the equation of this

Question

A polynomial is intersecting the x axis at - 4 and 2. Write the equation of this polynomial. y = x^2 + 2x - 8 x = 2 y = x^2 + 2x = 4 y = x^2 + 8x + 16 Roots of a polynomial are 0 and - 2. Determine this polynomial. > > v = [0 - 2] > > fx = roots (v) f = x + 2 > > v = [0 2] > > fx = polyroots (v) f = x^2 - 2x > > v = [0 - 2] > > fx = poly (v) f = x^2 + 2x > > v = [0 - 2] > > fx = roots (v) f = x^2 + 2x Write some MATLAB commands to form the derivative of the polynomial function s (t) = 3t^5 - 2t + 4. Another polynomial function such as k (t) will be obtained. > > S = [3 0 0 0 - 2 4] > > diff (s) > > s = [3 0 0 0 - 2 4] > > polyder (s) > > s = [3 0 0 0 - 2 4] > > polyint (s) > > s = [3 0 0 0 - 2 4] > > int (s)

Explanation / Answer

Question 8

Only y = x^2 + 2x - 8 is 0 at x= -4 and x = 2

16-8-8 = 0

4+4-8 = 0

Question 9:

v = [0 -2]

fx = poly(v)

question 10:

s = [3 0 0 0 -2 4]
polyder(s)

f = x^2 + 2x

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