Answer the following a. num1 = 48.2; addr = &num1; What is stored in addr? ____
ID: 3826814 • Letter: A
Question
Explanation / Answer
a) addr has the address of the variable num1.
b) The value in the variable pointed to xAddr is *xAddr
c) prices[5] = *(prices+5)
d) a=6,b=8,c=5
a<=b is True
b>=c is True
So a<=b && b>=c is True
So a<=b && b>=c || c>=b is True.
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