What is the data transfer rate in bps of a signal that is encoded using phase mo

Question

What is the data transfer rate in bps of a signal that is encoded using phase modulation with 32 different phase angles and a baud rate of 2500? a. 8,000 bps b. 10,000 bps c. 12, 500 bps d. 40,000 bps e. 80,000 bps I. A periodic signal completes one cycle in 0.02 second. What is the frequency? II. A sine wave completes 3600 cycles in one hour. What are its frequency and period? a. I. 25 Hz, II. 600 Hz, 0,00166 sec b. I. 25 Hz, II. 10 Hz, 0.1 sec c. I. 50 Hz, II. 10 Hz, 0.1 sec d. I. 50 Hz, II. 60 Hz, 0.0167 sec e. I. 50 Hz, II. 1 Hz, 1 sec Ten (10) voice signals are to be transmitted over a single high-speed telephone line. What is the bandwidth required (in bps) if standard analog to digital sampling rate is used and each sample is converted into 8 bit value? Assume that the highest frequency is 4000 Hz. a. 320,000 bps b. 640,000 bps c. 740,000 bps d. none of the above (Problems 58-60): Two computers are connected together through their serial ports and Hyper-terminal communication software. The communication settings between the two computers are as follows: (bit per second) pbs = 38400 data bits = 8 Parity bit = none Start bit = 1 stop bit = 1 A data file size of 38, 400 bytes is transferred between the two computers. The extra bits transmitted with the data are a. 19, 200 bits b. 28, 800 bits c. 38, 400 bits d. 76, 800 bits e. 115, 200 bits The efficiency of transmission is a. 72.7% b. 77.7% c. 80.0% d. 82.7% e. 85% The transmission time (the time that takes to complete the transmission of 38, 400 bytes and the extra bits) is a. 10 sec b. 11 sec c. 12 sec d. 13 sec d. 14 sec

Explanation / Answer

55. c. 12,500 bps    i.e., For 32 Phase Angles the data transfer rate will be 5 times of baud rate.

56. e. 1. 50 Hz , 1. Frequency =1/T =1/0.02=50 Hz

2. 1Hz, 1sec, i.e., Frequency = 1/1 = 1 Hz   Period = 1/1= 1sec

57. a 320,000 bps

58. d 76800 bits i.e., 38400*2 (1 start bit, 1 stop bit)

59. c 80%

60. a 10 secs i.e., 38400*8/38400+38400*2/38400 =10 secs

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