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Create a program that collects 10 numbers from the user (in any order) and then

ID: 3825827 • Letter: C

Question

Create a program that collects 10 numbers from the user (in any order) and then uses a bubble sort to display them in ascending order.

package bubblesort;

public class bubblesort1 {

      

    public static void main(String[] args) {

          

            //create an int array we want to sort using bubble sort algorithm

            int intArray[] = new int[]{5,90,35,45,150,3};

          

            //print array before sorting using bubble sort algorithm

            System.out.println("Array Before Bubble Sort");

            for(int i=0; i < intArray.length; i++){

                    System.out.print(intArray[i] + " ");

            }

          

            //sort an array using bubble sort algorithm

            bubbleSort(intArray);

          

            System.out.println("");

          

            //print array after sorting using bubble sort algorithm

            System.out.println("Array After Bubble Sort");

            for(int i=0; i < intArray.length; i++){

                    System.out.print(intArray[i] + " ");

            }

    }

    private static void bubbleSort(int[] intArray) {

          

            /*

             * In bubble sort, we basically traverse the array from first

             * to array_length - 1 position and compare the element with the next one.

             * Element is swapped with the next element if the next element is greater.

             *

             * Bubble sort steps are as follows.

             *

             * 1. Compare array[0] & array[1]

             * 2. If array[0] > array [1] swap it.

             * 3. Compare array[1] & array[2]

             * 4. If array[1] > array[2] swap it.

             * ...

             * 5. Compare array[n-1] & array[n]

             * 6. if [n-1] > array[n] then swap it.

             *

             * After this step we will have largest element at the last index.

             *

            * Repeat the same steps for array[1] to array[n-1]

             *

             */

          

            int n = intArray.length;

            int temp = 0;

          

            for(int i=0; i < n; i++){

                    for(int j=1; j < (n-i); j++){

                          

                            if(intArray[j-1] > intArray[j]){

                                    //swap the elements!

                                    temp = intArray[j-1];

                                    intArray[j-1] = intArray[j];

                                    intArray[j] = temp;

                            }

                          

                    }

            }

  

    }

}

Explanation / Answer

import java.util.Scanner;

public class Bubblesort1 {

   public static void main(String[] args) {

       //create an int array of 20 size

       int intArray[] = new int[10];

      

       System.out.println("Please enter 10 integers: ");

       Scanner sc = new Scanner(System.in);

       // filling with 10 integers

       for(int i=0; i<10; i++)

           intArray[i] = sc.nextInt();

      

       //print array before sorting using bubble sort algorithm

       System.out.println("Array Before Bubble Sort");

       for(int i=0; i < intArray.length; i++){

           System.out.print(intArray[i] + " ");

       }

       //sort an array using bubble sort algorithm

       bubbleSort(intArray);

       System.out.println("");

       //print array after sorting using bubble sort algorithm

       System.out.println("Array After Bubble Sort");

       for(int i=0; i < intArray.length; i++){

           System.out.print(intArray[i] + " ");

       }

   }

   private static void bubbleSort(int[] intArray) {

       /*

       * In bubble sort, we basically traverse the array from first

       * to array_length - 1 position and compare the element with the next one.

       * Element is swapped with the next element if the next element is greater.

       *

       * Bubble sort steps are as follows.

       *

       * 1. Compare array[0] & array[1]

       * 2. If array[0] > array [1] swap it.

       * 3. Compare array[1] & array[2]

       * 4. If array[1] > array[2] swap it.

       * ...

       * 5. Compare array[n-1] & array[n]

       * 6. if [n-1] > array[n] then swap it.

       *

       * After this step we will have largest element at the last index.

       *

       * Repeat the same steps for array[1] to array[n-1]

       *

       */

       int n = intArray.length;

       int temp = 0;

       for(int i=0; i < n; i++){

           for(int j=1; j < (n-i); j++){

               if(intArray[j-1] > intArray[j]){

                   //swap the elements!

                   temp = intArray[j-1];

                   intArray[j-1] = intArray[j];

                   intArray[j] = temp;

               }

           }

       }

   }

}

/*

Sample run:

Please enter 10 integers:

5 1 99 34 12 9 0 54 22 10

Array Before Bubble Sort

5 1 99 34 12 9 0 54 22 10

Array After Bubble Sort

0 1 5 9 10 12 22 34 54 99

*/

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