PLEASE C++ ONLY The task is to find the length of the longest subsequence in a g
ID: 3822054 • Letter: P
Question
PLEASE C++ ONLY
The task is to find the length of the longest subsequence in a given array of integers such that all elements of the subsequence are sorted in ascending order.
For example, the length of the LIS for {15, 27, 14, 38, 26, 55, 46, 65, 85 } is 6 and the longest increasing subsequence is {15, 27, 38, 55, 65, 85}.
Input : arr[] = {3, 10, 2, 1, 20}
Output : Length of LIS = 3
The longest increasing subsequence is 3, 10, 20
Input : arr[] = {3, 2}
Output : Length of LIS = 1
The longest increasing subsequences are {3} and {2}
Input : arr[] = {50, 3, 10, 7, 40, 80}
Output : Length of LIS = 4
The longest increasing subsequence is {3, 7, 40, 80}
Rule:
Let, arr[0..n-1] be the input array and L(i) be the length of the LIS ending at index i such that arr[i] is the last element of the LIS.
Then, L(i) can be recursively written as:
L(i) = 1 + max( L(j) ) where 0 < j < i and arr[j] < arr[i]; or
L(i) = 1, if no such j exists.
To find the LIS for a given array, we need to return max(L(i)) where 0 < i < n.
Assignment (point: 20)
Follow the stated rules, complete the L = [....] array and find out what is the longest increasing subsequence for
arr = [100, 30, 90, 20, 29, 70, 109, 2, 22, 210, 55]
Show/Explain each step of filling L[i].
This is an open problem. You can use online resources to understand the problem. Then fill out the L array.
[Note: Do something similar that we have done in class for LCS problem in a worksheet filling out a 2D array
Arr= [20, 29, 70, 109, 210]
Length= 5
Explanation / Answer
#include<iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
int a[]={50, 3, 10, 7, 40, 80};
int b[50],i,j,n,ls[50];
n=sizeof(a)/sizeof(a[0]);
int maxlen=0,end=-1;
b[0]=-1;
for(i=0;i<n;i++)
{
ls[i]=1;
for(j=0;j<i;j++)
{
if(a[i]>a[j] && ls[i]<ls[j]+1)
{
ls[i]=ls[j]+1;
b[i]=j;
}
}
if(ls[i]>maxlen)
{
end=i;
maxlen=ls[i];
}
}
cout<<maxlen<<endl;
vector<int> v;
for(int k=end;k!=-1;k=b[k])
{
v.push_back(a[k]);
}
reverse(v.begin(), v.end());
for(int x: v) {
cout << x << ' ';
}
return 0;
}
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