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3. (20 Points) Fernandez Engineering is evaluating 4 alternative approaches for

ID: 381831 • Letter: 3

Question

3. (20 Points) Fernandez Engineering is evaluating 4 alternative approaches for meeting its internal computing needs. After careful examination of the proposals, the Proposal Evaluation Task Force has developed the following matrix: PW of Adherence to Upgrade Compatibility Life Cycle Cost Technical Capability to Existing Approach (SK)Requirements -380 530 -420 -475 System 4 4 4 10 Note: ranking scale Y worst; 10 best Upon careful consideration, the Task Force has assigned the following scores o the attributes 75 to Cost, 25 to Adherence to Technical Requirements, 10 to Upgrade Capability and 50 to Compatibility to Existing System. N( Based on a SA W analysis, which approach should be should be chosen? Please Note: 1. To receive 2. All Vij rating values must be on preferred. full credit you must use normalized weights in your solution. a relational scale of 1-10, 10 being most

Explanation / Answer

Convert the PW of life cycle cost t relational scale with -380 having a ranking of 10 and -530 a ranking of 1.

Slope = (10-1)/(-380-(-530)) = 0.06

Intercept = 1 - (-530)*0.06 = 32.8

Ranking of C = -420*0.06+32.8 = 7.6

Ranking of D = -475*0.06+32.8 = 4.3

Normalized weight for Cost = 75/(75+25+10+50) = 0.46875

Normalized weight for Adherence to Tech req = 25/(75+25+10+50) = 0.15625

Normalized weight for Upgrade capability = 10/(75+25+10+50) = 0.0625

Normalized weight for Compatibility to Existing system = 50/(75+25+10+50) = 0.3125

SAW analysis

Weighted ranking score of approach A = 10*0.46875 + 4*0.15625 + 5*0.0625 + 4*0.3125 = 6.875

Weighted ranking score of approach B = 1*0.46875 + 8*0.15625 + 8*0.0625 + 4*0.3125 = 3.469

Weighted ranking score of approach C = 7.6*0.46875 + 9*0.15625 + 7*0.0625 + 6*0.3125 = 7.281

Weighted ranking score of approach D = 4.3*0.46875 + 10*0.15625 + 3*0.0625 + 9*0.3125 = 6.578

Weighted score of approach C is the greatest.

Therefore, approach C should be chosen.

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