*AS ALWAYS ALL QUERIES MUST BE DATA INDEPENDENT*\' (PLEASE COMPLETE IN SQL ORACL
ID: 3818139 • Letter: #
Question
*AS ALWAYS ALL QUERIES MUST BE DATA INDEPENDENT*' (PLEASE COMPLETE IN SQL ORACLE)
Get the number of customers that have same preference as Patel, M
Give the names of customers that have similar preferences as Patel, M (note if customer Patel, M has two flavor preferences, then we want names of customers who also prefer either one or both of those flavors).
NEEDED INFORMATION!!!!!
ICECREAM (Ice_cream_ID, Ice_cream_flavor, price, years_first_offered, sellling _status)
INGREDIENT( Ingredient_ID, Ingredient_name, cost)
RECIPE (Ice_cream_ID, ingredient_ID, quantity_used)
CUSTOMER (Cust_ID, Cust_name, year_born)
Customer_and_Flavor_id (cust_id, Flavor_id)
WHERE:
Ice_cream_ID is the internal Id given to an ice cream.
Ingredient_ID is the internal Id given to an ingredient
selling_staus is an internal control which keeps track of ice cream sales as high, low, medium or none. If no figures are available this field has no value.
Years_first_offered is the year that ice cream was first offered
quantity_used is the amount of ingredient used in a given ice cream
ICECREAM TABLE
INGREDIENT TABLE
RECIPE TABLE
CUSTOMER TABLE
CUSTOMER_AND_FLAVOR_ID TABLE
ICE CREAM ID ICE CREAM FLAVOR 101 berry 201 vanilla 211 cherry 311 chocolate 321 strawberry 405 pistachio 406 almond 307 blackberry 510 mint 520 Cookie 525 green tea ICE CREAM ID ICE CREAM FLAVOR 540 raspberry 545 banana 550 pineapple 560 coconut 15 rows selected. PRICE YEAR FIRST OFFERED SELLIN 2010 null 1981 high 2.5 1976 low 1981 high 1961 high 2.5 2012 low 2010 null 2015 null 1.5 1998 medium 2001 medium 4.5 2012 low PRICE YEAR FIRST OFFERED SELLIN 2012 null 1992 medium 1.5 2.5 2001 high 3.25 2012 mediumExplanation / Answer
Names of customers with similar preference as patel, P
select distinct(CUST_NAME) from CUSTOMER c, CUSTOMER_AND_FLAVOR_ID cf where cf.FLAVOR_ID in (select FLAVOR_ID from CUSTOMER c, CUSTOMER_AND_FLAVOR_ID cf where c.cust_ID= cf.cust_ID and c.CUST_NAME='Patel,P')
Number of customers
select count(*) from (select distinct(CUST_NAME) from CUSTOMER c, CUSTOMER_AND_FLAVOR_ID cf where cf.FLAVOR_ID in (select FLAVOR_ID from CUSTOMER c, CUSTOMER_AND_FLAVOR_ID cf where c.cust_ID= cf.cust_ID and c.CUST_NAME='Patel,P')) ntable;
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