Predict the output when the following program segment is executed. Enter your re

Question

Predict the output when the following program segment is executed.

Enter your result in the space provided.

int[ ][ ] arrayNums = new int[5][4];

arrayNums[0][0] = 40;

arrayNums[0][1] = 72;

arrayNums[0][2] = 37;

arrayNums[0][3] = 23;

arrayNums[1][0] = 20;

arrayNums[1][1] = 19;

arrayNums[1][2] = 76;

arrayNums[1][3] = 18;

arrayNums[2][0] = 50;

arrayNums[2][1] = 72;

arrayNums[2][2] = 31;

arrayNums[2][3] = 39;

arrayNums[3][0] = 43;

arrayNums[3][1] = 30;

arrayNums[3][2] = 88;

arrayNums[3][3] = 19;

arrayNums[4][0] = 40;

arrayNums[4][1] = 78;

arrayNums[4][2] = 56;

arrayNums[4][3] = 21;

int rows = 5;

int columns = 4;

int i, j, sum = 0;

for (i = 0; i < rows ; i++) { for (j = 0; j < columns ; j++)

{ System.out.print( arrayNums[i][j] + " " );

} sum += arrayNums[i][j];

System.out.println( "" ); }

//the output is: __________

Explanation / Answer

Output will be error:

40 72 37 23

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException:

---------------------------------------------------------------------------------------------------------------

for (i = 0; i < rows ; i++)
{
for (j = 0; j < columns ; j++)
{
System.out.print( arrayNums[i][j] + " " );
}
sum += arrayNums[i][j];
System.out.println( "" );
  
}

In the Above code where i have bloted, you are accessing the data of arrayNums where

i and j values will be

i == 0

j == 4

where you are accessing the values which is not in the scope of arrayNums

How this was occured>?

for (j = 0; j < columns ; j++)
{
System.out.print( arrayNums[i][j] + " " );
}

In the above statement you are looping j from 0 to 4 and printing the values, the condition fails when j is greater then 4 i.e (4 < 4)

in the next statement you are accessing the unknow value of arrayNums

arrayNums[0][4] which leads to an error.

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