Quiz 6 Chapter 5 Subnets ass B A company Bit-by-Bit Inc. has been assigned a net

Question

Quiz 6 Chapter 5 Subnets ass B A company Bit-by-Bit Inc. has been assigned a network IP address of 155.1 It has three divisions that need a total of 85 subnets. You are the network administrator for the company and are responsible for creating the subnets. Please answer the following questions. (22 points) 1. many bits do you need to borrow from the host bits for the subnet field (l point) How 2 bilr 2. What is the maximum number of host addresses per subnet? point) 3. What is the maximum number of IP addresses that can be assigned to a host device per subnet? (1 point) 4. What is the subnet mask in binary representation 1 point) 5. What is the subnet mask in decimal representation? 1 point) 6. Please indicate the following details for the first three subnets and last possible subnet in the network (16 points) a. Subnet number ss es s b. Subnet address c. Range of host addresses that can be assigned to a host device. 55. d. Direct Broadcast address is 5. 1.255. 255 66 assign the IP address 155.1.5.255 to a host device in the network? (1 point) 7. Can you th Ranya boll ou 6 oo ooool oooooooo oooooooo oo S

Explanation / Answer

Here I have tried to explain all the concerns from the above furnished question. Hope this will hepl you out mosy ways:

IP=155.1.0.0
Subnet Mask = 255.255.128.0
2.Maximum Number of Subnets= 2
Nodes/Hosts per Network = 32768

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Subnet Calculator Explanation
This calculator will calculate the subnet mask to use, given a TCP/IP network address and the number of subnets or nodes per subnet required.

To create the subnet mask, first remember that the purpose of the subnet mask is to separate the (32 bit) ip address into the network prefix and the host number. If a bit in the subnet mask is 1, the corresponding bit in the IP address is part of the network address; if the bit in the subnet mask is 0, the corresponding bit in the IP address is part of the host address.

First depict the ip address in binary. Take 155.1.0.0 and convert to binary:

          ip address: 10011011.00000001.00000000.00000000

First we determine what class of address it is:

   If the first bit is 0 it is a Class A address
   If the first two bits are 10 it is a Class B address
   If the first three bits are 110 it is a Class C address
   If the first four bits are 1110 it is a Class D multicast address
   If the first four bits are 1111 it is a Class E experimental address

Your example is a Class B address. Since you want to subnet as a Class B, the default subnet mask would be:

         subnet mask: 11111111.11111111.00000000.00000000

The formula for figuring out the number of 'network' bits in a subnet mask is

         2^n=number of subnets          (2^n means '2' to the power of 'n')

Since you know the number of subnets, you need to find 'n'.

Because you want 2 subnet(s), you want to add 1 - '1' bits to the default subnet mask since 2 = 2 ^ 1.
This will give you the following subnet mask:

         subnet mask: 11111111.11111111.10000000.00000000

Which is referred to as /17 or in dotted decimal notation as 255.255.128.0
If the Explain feature does not show your example, but only shows the deafult example (10.11.12.13) then likely yor

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Mask Bits=17
Host per Subnet =32766
6. c)Host address range =155.1.0.1 - 155.1.127.254
6. b)Subnet ID = 155.1.0.0
6. d) Broadcast Adress = 155.1.127.255
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Subnet Calculator Explanation
This calculator will calculate the network address, the host address and the broadcast address for a given TCP/IP address and subnet mask.

These are actually fairly straightforward calculations. The easiest way to do it is to depict both the ip address and the subnet mask in binary. Take 155.1.0.0 with subnet mask 255.255.128.0 listed in binary:

          ip address: 10011011.00000001.00000000.00000000
         subnet mask: 11111111.11111111.10000000.00000000

If you do a binary AND between these two numbers, you get the network address:

          ip address: 10011011.00000001.00000000.00000000
         subnet mask: 11111111.11111111.10000000.00000000
              -----------------------------------AND
     network address: 10011011.00000001.00000000.00000000

which translated back to dotted decimal notation is 155.1.0.0

To get the host portion, invert the subnet mask and again perform a binary AND with the ip address:

          ip address: 10011011.00000001.00000000.00000000
inverted subnet mask: 00000000.00000000.01111111.11111111
              -----------------------------------AND
        host portion: 00000000.00000000.00000000.00000000

which translated back to dotted decimal notation is 0.0.0.0

To obtain the broadcast address, again it is simplest to look at it in binary. Take the inverted subnet mask and perform a binary XOR with the network address:

     network address: 10011011.00000001.00000000.00000000
inverted subnet mask: 00000000.00000000.01111111.11111111
              -----------------------------------XOR
   broadcast address: 10011011.00000001.01111111.11111111

which translated back to dotted decimal notation is 155.1.127.255
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4.Subnet Bitmap =10nnnnnn.nnnnnnnn.shhhhhhh.hhhhhhhh
5.Subnet Decimal representation : 9B.01.00.00
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Subnet Calculator Explanation

This calculator will convert between the various notations for IP addresses.

The easiest way to do it is to depict the ip address in binary. Take 2600534016 and convert to binary using any calculator that will do decimal to binary conversion (like the one that comes with Windows/95/98/NT):

        binary address: 10011011.00000001.00000000.00000000

Then convert each octet back to decimal and you get: 155.1.0.0

If you want to calculate the decimal address from the dottted decimal address, perform the following calculation:

   (first octet * 16777216) + (second octet * 65536) + (third octet * 256) + (fourth octet)

Using your values:

   155*16777216 + 1*65536 + 0*256 + 0 = 2600534016

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7. Yes

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