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Program in C/ C++ The horizontal and vertical motion of the center of mass of an

ID: 3813786 • Letter: P

Question

Program in C/ C++

The horizontal and vertical motion of the center of mass of an airplane in the vertical plane can be described using a two degrees-offreedom 2DOF) model. night path 7 horizontal You will learn in Aircraft Stabilit and Control thatthe equations of motion ofthe aircraft can be written as Isin y (T Icos where is altitude and xia the horizontal distance travelled. Other parameters in the equations are: T thrust vertical velocity D- drag g gravity aircraft mass LE lift y flight path angle Lift, drag, and flight path angle are determined by: where and Veare components of flight speed V- in the x and z directions. Note that:

Explanation / Answer

#include <stdio.h>
#include <stdlib.h>

struct btnode
*root = NULL, *temp = NULL, *t2, *t1;

void delete1();
void insert();
void delete();
void inorder(struct btnode *t);
void create();
void search(struct btnode *t);
void preorder(struct btnode *t);
void postorder(struct btnode *t);
void search1(struct btnode *t,int data);
int smallest(struct btnode *t);
int largest(struct btnode *t);

int flag = 1;

void main()


/* To create a node */
void create()


/* recursive function to perform inorder traversal of tree */
void inorder(struct btnode *t)

else if ((data < t->value))
  
else if ((data==t->value))
  
}

/* To delete a node */
void delete1(struct btnode *t)

else
  
t = NULL;
free(t);
return;
}

/* To delete node having one left hand child */
else if ((t->r == NULL))
  
else if (t1->l == t)
  
else
  
t = NULL;
free(t);
return;
}

/* To delete node having manus kid */
else if (t->l == NULL)
  
else if (t1->r == t)
t1->r = t->r;
else
t1->l = t->r;
t == NULL;
free(t);
return;
}

/* To delete node having 2 kid */
else if ((t->l != NULL) && (t->r != NULL))
  
else
  
search1(root, k);
t->value = k;
}

}

/* to search out the littlest part within the right sub tree */
int smallest(struct btnode *t)

else
come (t->value);
}

/* to search out the biggest part within the left sub tree */
int largest(struct btnode *t)

else
return(t->value);
}

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