Jameis Winston is about to throw a pass to Mike Evans running free across the mi

Question

Jameis Winston is about to throw a pass to Mike Evans running free across the middle of the field. Winston is 6 feet tall and Evans is straight down the field 60 feet away. The equation that describes the motion of the football (assuming that Winston doesn't fumble the ball which he's done more than any other quarterback) is y = x tan(theta) -1/2 x^2 g/v^2_o 1/cos^2(theta) + h where x and y are the horizontal and vertical distance respectively, g = 32.2 ft/s^2 is the acceleration due to gravity, and v_o is the initial velocity of the football as it leaves Jameis Winston's hand. If you start with a_o = 0 and b_0 = pi/4, and v_o = 50 ft/sec, x = 60ft., h = 6ft, and y = 7ft, use your Newton Method to find the angle theta Winston must launch the ball to within 5 decimal places.

Explanation / Answer

The angel is of 45°. I simplied the above equation and then I got the angle as 45°.

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