Given the following characteristics: Size of a record = 210 bytes Number of byte

Question

Given the following characteristics: Size of a record = 210 bytes Number of bytes per sector = 512 Number of sectors per track = 44 Number of tracks per cylinder = 8 Number of cylinders per drive = 4096 Calculate: a) The maximum size of a data file that can be stored in 5 cylinders b) using the specifications in question (a), how many tracks are required to store a data file of 40,000 records. c) The total size of the un-used space (internal fragmentation) caused by storing the data file in (b).

Explanation / Answer

solution with given specifications:

a)maximum size of data that can be stored in 1 cylinder = (number of tracks/cylinder)* (number of sectors/track)*(number of bytes/sector)

=8*44*512*5 bytes

=180224 bytes

for 5 cylinder = 180224 * 5

= 901120 bytes

b) 1 record size =210 bytes

40,000 record =40,000*210

=84,00,000 bytes

number of tracks =(40,000 * 210)/(44*512)

= 22,528

c) Internal fragmentation

record size =210 bytes sector size =512 bytes

only 2 records can be stored in each sector.

  

=512-(2*210)= 512-420= 82 bytes is unused in each sector . this leads to fragmentation.

total internal fragmentation =(40,000/2)*82 =1,64,000 bytes

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