Create an array of 5 integers (any numbers you want). Print each number in the a
ID: 3811022 • Letter: C
Question
Create an array of 5 integers (any numbers you want). Print each number in the array plus 50 Create an array of 5 values of type double. Your program will print the average of all these values. Create an array of 5 integer values. Your program will print the PRODUCT of all numbers in the array. Create a program that asks the user to TYPE 10 integer values of an array. After the user types these numbers, the program will print each number squared. (Use a for loop) Create a program that asks the user to type 5 integer values. After getting the values, your program will then display the consecutive integers whose difference is minimum. For example, if had the following array values: {40, 5, 7, 100, 17} The program would display 5 and 7, since they are consecutive in the array, and since their difference is 2 (the smallest).Explanation / Answer
7.1)
#include <iostream>
using namespace std;
int main()
{
int arr[5]={2,3,4,5,6};
for(int i=0;i<5;i++)
{
int sum=0;
sum = arr[i]+50;
cout<<sum;
cout<<endl;
}
return 0;
}
7.2)
#include <iostream>
using namespace std;
int main()
{
double arr[5]={2,3,4,5,6};
double sum=0;
for(int i=0;i<5;i++)
{
sum = sum+arr[i];
}
cout<<"Average:"<<sum/5;
cout<<endl;
return 0;
}
7.3)
#include <iostream>
using namespace std;
int main()
{
double arr[5]={2,3,4,5,6};
double sum=1;
for(int i=0;i<5;i++)
{
sum = sum*arr[i];
}
cout<<"Result:"<<sum;
cout<<endl;
return 0;
}
7.4)
#include <iostream>
using namespace std;
int main()
{
int arr[10];
int sum=0;
cout<<"Enter 10 integer values for array:"<<endl;
for(int i=0;i<10;i++)
{
cin>>arr[i];
}
for(int i=0;i<10;i++)
{
sum=arr[i]*arr[i];
cout<<"Square of"<<arr[i]<<":"<<sum;
cout<<endl;
}
return 0;
}
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