q15) CONSIDER THE FOLLOWING CODE: void Question() { int x = 12; int y = 12; doub

Question

q15)

CONSIDER THE FOLLOWING CODE:
void Question()
{
      int x = 12;
      int y = 12;
      double sum = y + x;
      for (int i = 1; i < 7; i++)
      {
            if (i % 2 == 1)
                  sum += 4 * y;
            else
                  sum += 2 * y;
      }
      double Area = (y - x) / 3 * sum;
      cout << "The area under the curve is : " << Area << endl;
}

Select one:

a. The area under the curve is : 24

b. The area under the curve is : 0

c. The area under the curve is : 10

d. The area under the curve is : 144

please explain how you get the answer. Thank you

Explanation / Answer

the answer is b.The area under the curve is : 0

in the Question, x=12,y=12, sum=x+y, therefore sum=24

then for loop, this loop which will be executed for 6 times.

inside the for loop, in the if condition, we checking for i % 2 == 1,that is dividing counter variable by 2 and
checking for remainder 1, if this condition is true,that is remainder is 1,then we are doing sum=sum+4 *y,

otherwise, that is,if the remainder is not equal to 1, then we are doing sum=sum+2*y

after exiting from the loop, variable sum will have some value(sum=240). Then area is calculated by the (y-x)/3*sum formula,

since x and y are equal, x-y in the formula gives zero, therefore result is zero.
then result is printed.

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