Python Functions sum_of_digits(n): Given a non-negative integer n, calculate and

Question

Python

Functions sum_of_digits(n): Given a non-negative integer n, calculate and return the sum of all its digits. Assume: n is a non-negative integer. Return value: an integer. Examples: sum_of_digits(0) rightarrow 0 # only digit is 0 sum_of_digits (204) rightarrow 6 # 2+0+4 = 6 multiply_until_total_reached(original, total, n): Starting with a positive integer original, keep multiplying original by n and calculate the sum of all multiples generated including original until the sum is no longer smaller than total. Return the minimum number of multiplications needed to reach at value at or above the given total. Assume: All three arguments are integers: original and n are positive. Return value: an integer. Examples: multiply_until_total_reached (1, 5, 2) rightarrow 2 # 1*2=2, (1+2)5, 2 multiplications needed multiply_until_total_reached (1, 15, 2) rightarrow 3 # 1*2=2, (1+2)

Explanation / Answer

code: for first 3 function

import os
import sys

def sum_of_digits(n):
summ=0
while n!=0:
summ+= int(n%10)
n=n/10
return summ

def multiply_until_total_reached(original,total,n):
cnt=0
while original<=total:
original=original*n
cnt+=1
return cnt-1

def replicate(xs,n):
newxs=[]
for i in xs:
for j in range(0,n):
newxs.append(i)

return newxs

print replicate([1,2,2,3],2)

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