Database: (Please make short answers) 6. Find the names and ids of the students
ID: 3803278 • Letter: D
Question
Database: (Please make short answers)
6. Find the names and ids of the students who have taken exactly one course in the Spring 2010 semester.
7. Find the names and ids of the students who have taken at most one course in the Spring 2010 semester. Notice, at most one means one or zero. So, the answer should include students who did not take any course during that semester
8. Write a query that uses a derived relation to find the student(s) who have taken at least two courses in the Spring 2010 semester. Schema of the output should be (id, number_courses). Remember: derived relation means a subquery in the from clause.
9. Write a query that uses a scalar query in the select clause to find the number of distinct courses that have been taught by each instructor. Schema of the output should be (name, id, number_courses).
10. Use an outer join to find names of instructors who did not teach any course in the Spring 2010 semester.
11. [Extra credit: 10 points] Write a query that uses the with clause or a derived relation to find the id and number of courses that have been taken by student(s) who have taken the most number of courses. Schema of the output should be (id, number_courses).
create table classroom
(building varchar(15),
room_number varchar(7),
capacity numeric(4,0),
primary key (building, room_number)
);
create table department
(dept_name varchar(20),
building varchar(15),
budget numeric(12,2) check (budget > 0),
primary key (dept_name)
);
create table course
(course_id varchar(8),
title varchar(50),
dept_name varchar(20),
credits numeric(2,0) check (credits > 0),
primary key (course_id),
foreign key (dept_name) references department
on delete set null
);
create table instructor
(ID varchar(5),
name varchar(20) not null,
dept_name varchar(20),
salary numeric(8,2) check (salary > 29000),
primary key (ID),
foreign key (dept_name) references department
on delete set null
);
create table section
(course_id varchar(8),
sec_id varchar(8),
semester varchar(6)
check (semester in ('Fall', 'Winter', 'Spring', 'Summer')),
year numeric(4,0) check (year > 1701 and year < 2100),
building varchar(15),
room_number varchar(7),
time_slot_id varchar(4),
primary key (course_id, sec_id, semester, year),
foreign key (course_id) references course
on delete cascade,
foreign key (building, room_number) references classroom
on delete set null
);
create table teaches
(ID varchar(5),
course_id varchar(8),
sec_id varchar(8),
semester varchar(6),
year numeric(4,0),
primary key (ID, course_id, sec_id, semester, year),
foreign key (course_id,sec_id, semester, year) references section
on delete cascade,
foreign key (ID) references instructor
on delete cascade
);
create table student
(ID varchar(5),
name varchar(20) not null,
dept_name varchar(20),
tot_cred numeric(3,0) check (tot_cred >= 0),
primary key (ID),
foreign key (dept_name) references department
on delete set null
);
create table takes
(ID varchar(5),
course_id varchar(8),
sec_id varchar(8),
semester varchar(6),
year numeric(4,0),
grade varchar(2),
primary key (ID, course_id, sec_id, semester, year),
foreign key (course_id,sec_id, semester, year) references section
on delete cascade,
foreign key (ID) references student
on delete cascade
);
create table advisor
(s_ID varchar(5),
i_ID varchar(5),
primary key (s_ID),
foreign key (i_ID) references instructor (ID)
on delete set null,
foreign key (s_ID) references student (ID)
on delete cascade
);
create table time_slot
(time_slot_id varchar(4),
day varchar(1),
start_hr numeric(2) check (start_hr >= 0 and start_hr < 24),
start_min numeric(2) check (start_min >= 0 and start_min < 60),
end_hr numeric(2) check (end_hr >= 0 and end_hr < 24),
end_min numeric(2) check (end_min >= 0 and end_min < 60),
primary key (time_slot_id, day, start_hr, start_min)
);
create table prereq
(course_id varchar(8),
prereq_id varchar(8),
primary key (course_id, prereq_id),
foreign key (course_id) references course
on delete cascade,
foreign key (prereq_id) references course
);
Explanation / Answer
Query for question 6 :
select Name, ID from student where ID in (select ID from takes where (semester = 'spring' and year=2010) group by id having count(id) = 1);
Query for question 7:
select Name, ID from student where ID in (select ID from takes where (semester = 'spring' and year=2010) group by id having count(id) <= 1);
Query for question 8:
select id, subquery1.number_course as number_course from student,
(select ID, sum(course_id) as number_course from takes group by id having sum(course_id) = 2) subquery1
where (semester = 'spring' and YEAR = 2010);
Query for question 10:
select instructor.name from instructor
left outer join
on takes
instructor.id = takes.id;
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