2. Given the length class interface below: class length public: length(); length

Question

2. Given the length class interface below: class length public: length(); length (int f, int i); initialized Postconditin: a new length object is declared and void set Feet (int); known as the "mutator" function object is changed Postcondition: feet date member of the calling void set Inches (int); int get Feet() function is returned known as the "accessor" calling object Postcondition: feet data member of the int get Inches bool compare (length& obj2); compare the the calling object to obj3 otherwise condition: return true if calling object is longer; return false void display(); object like 5'7" for 5 feet 7 inches Postcondition: display the contents of the callig than 12 Note that the inches part must be less length& obj2); object and obj2 Postcondition: Display the contents of the sum of the calling Note that the inches must be less than 12 double area length& obj2); obj width Post return the area of a rectangle where calling represents the sqare ft. and obj2 represents the length of the rectangle Area is measure in

Explanation / Answer

Here is the code for you:

#include <iostream>
class length
{
    int feet;
    int inches;
    public:
        length()
        {
           feet = inches = 0;
        }
        length(int f, int i)
        {
           feet = f; inches = i;
        }
        void setFeet(int f)
        {
           feet = f;
        }
        void setInches(int i)
        {
           inches = i;
        }
        int getFeet()
        {
           return feet;
        }
        int getInches()
        {
           return inches;
        }
        bool compare(length& obj2)
        {
           return feet == obj2.feet && inches == obj2.inches;
        }
        void display()
        {
           std::cout << feet + inches / 12 << "'" << inches%12 << """ << std::endl;
        }
        length add(length& obj2)
        {
           return length(feet + obj2.feet, inches + obj2.inches);
        }
        double area(length& obj2)
        {
           int totalInches = (feet * 12 + inches) * (obj2.feet * 12 + obj2.inches);
           return totalInches / 12.0;
        }
};
void display(length obj)
{
    obj.display();
}

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.