Bookmark I need to rotate a matrix n*m 90º on C++ where n!=m or n=m I need to be

ID: 3802960 • Letter: B

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I need to rotate a matrix n*m 90º on C++ where n!=m or n=m I need to be able to do both. I was given these instructions:

•Takes a signed integer as the argument corresponding to an angle in degrees and rotates the image in-place by that angle.

•You can assume the angle in degrees will always be a multiple of 90.

•Positive value of degrees means an anti-clockwise rotation while negative means a clockwise rotation.

•You should allow for cascading calls so that A.Rotate(90).Rotate(90) finally rotates the image A by 180 degrees.

include <bits/stdc++.h>

#define N 4

using namespace std;

void display(int m[N][N]); //function declaration for displaying the matrix

void rotate(int mat[][N]) //function declaration and defination for rotation

{for (int i=0; i<N/2; i++)

{for (int k=i; k<N-i-1; k++)

{ int temp=m[i][k]; // storing current value in temporary variable

m[i][k]=mat[k][N-1-i]; // shifting values from right cell to the cell on top

m[k][N-1-i]=m[N-1-i][N-1-k]; // shifting values from bottom cell to right

m[N-1-i][N-1-k]=m[N-1-k][i]; // shifting values from left cell to bottom cell

m[N-1-k][i] = temp; // value assigned from temp to left cell

}

void display(int m[N][N]) //function defination for displaying the matrix

{ for (int a=0; a<N; a++)

{ for (int b=0; b<N; b++)

printf("%2d ", m[a][b]);

printf(" ");

}

printf(" ");

}

int main()

{

int m[N][N]={ {1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12}, {13, 14, 15, 16} };

display(m); // Prints the current matrix

rotate(m); // rotates the current matrix

display(m); //Prints the rotated matrix

return 0;

}

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