From an earlier exercise, we computed the area of a circle using the following f

Question

From an earlier exercise, we computed the area of a circle using the following formula, where R is the radius of the circle and pi represents the value for Pi. Modify the solution to use a loop to prompt the user for a valid radius if they try to enter a value below 0. the loop should repeat until they enter a good radius. Area = pi R^2 #include int main(void) {double Pi; double radius; double area; Pi = 3.14159;//STEP 1: Prompt the user for the radius and read it in, use a loop//that repeats until the user enters a good radius. Please tell the//user what was wrong if they entered a bad radius.//Compute the area of the circle and the volume of the sphere area = Pi * radius * radius; print f("For a radius of %.1lf ", radius); print f("The Area of the corresponding circle is: %.3lf ", area); print f("The Volume of the corresponding sphere is: %.3lf", volume); print f(" End Program. "); return 0;}

Explanation / Answer

#include <stdio.h>

int main(void) {
   double Pi;
   double radius;
   double area;
   double volume=0.0;
   Pi=3.14159;
   do
   {
   printf("Enter the value of the radius ");
   scanf("%lf",&radius);
   if(radius<=0)
   {
   printf("The values of radius is less than 0.Please enter a valid number ");
   }
   }while(radius<=0);
   area=Pi*radius*radius;
   volume=1.3333*Pi*radius*radius*radius;
   printf("For a radius of %.1lf ",radius);
   printf("The Area of the correspondong circle is : %.3lf ",area);
   printf("The Volume of the correspondong sphere is : %.3lf ",volume);
   printf(" End Program. ");
   return 0;
  
}

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