Make absolutely no changes to main() . Change function backwards so that the ele
ID: 3801904 • Letter: M
Question
Make absolutely no changes to main(). Change function backwards so that the elements of the array are swapped in order for elements to be in reverse order. That is, arr[0] will be 16, arr[1] will be 5, etc. But backwards() must work no matter what values are in the array and for all values passed in for number. After it is corrected this program should output:
16
5
3
17
8
2
#include <iostream>
using namespace std;
void backwards(int [], int);
int main()
{
int arr[] = {2,8,17,3,5,16}; int i;
backwards(arr,6);
for (i = 0; i< 6; i++)
cout<<arr[i]<<endl;
//system("pause");
return 0;
}
void backwards(int array[], int number)
{
/*Pre: array[] - array of integers
number - number of elements in the array that have values
Post: Nothing
Purpose: Reverse the order of the elements of an array */
int i; int temp;int j;
for(i = 0; i < number;i++)
{
temp = array[i];
array[i] = array[number - 1 - i];
temp = array[number - 1 - i];
}
return;
}
Explanation / Answer
Hi
I have fixed thee issue and highlighted the code changes below
#include <iostream>
using namespace std;
void backwards(int [], int);
int main()
{
int arr[] = {2,8,17,3,5,16}; int i;
backwards(arr,6);
for (i = 0; i< 6; i++)
cout<<arr[i]<<endl;
//system("pause");
return 0;
}
void backwards(int array[], int number)
{
/*Pre: array[] - array of integers
number - number of elements in the array that have values
Post: Nothing
Purpose: Reverse the order of the elements of an array */
int i; int temp;int j;
for(i = 0; i < number/2;i++)
{
temp = array[i];
array[i] = array[number - 1 - i];
array[number - 1 - i]=temp;
}
return;
}
Output:
sh-4.2$ g++ -o main *.cpp
sh-4.2$ main
16
5
3
17
8
2
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.