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1. After comparing the destination IP address to its routing table entries, a ro

ID: 3801287 • Letter: 1

Question

1. After comparing the destination IP address to its routing table entries, a router will do one of three things. List each of the possible scenarios and the condition which causes it to be carried out

2. Suppose a destination computer receives several packets from a source. How can it be sure that the fragments belonging to a datagram are not mixed with the fragments belonging to another datagram

3. Which fields of the IPv4 main header may change from router to router

4. Hosts are grouped into networks and subnetworks for various reasons. Name three

Explanation / Answer

1ANS: I explained this with the following example

A switch has the accompanying (CIDR) passages in its directing table

Address/mask   Next bounce

135.46.56.0/22   Interface 0

135.46.60.0/22   Interface 1

192.53.40.0/23   Router 1

default   Router 2

For each of the accompanying IP addresses, what does the switch do if a bundle with that address arrives?

a. 135.46.63.10

Ans: The switch will check the directing passage beginning with the longest prefix (/23), 192.53.40.0/23. /23 mean system address is 23 bit and the relating system veil is 255.255.255.0.

135.45.63.10 and 255.255.254.0=135.45.62.0 != 192.53.40.0 hence this section does not coordinate. Next longest prefix is/22. 135.45.63.10 and 255.255.252.0=135.45.60.0. It matches 135.45.60.0/22 directing passage, along these lines the parcel will be steered out over Interface 1. With snappy perception, we can skirt the directing passage with 192.53.40.0/23 however the switch can't.

b. 135.46.57.14

Ans: 135.46.57.14 and 255.255.252.0=135.45.56.0. It matches 135.45.56.0/22 directing section and the parcel will be steered out over Interface 0.

c. 135.46.52.2

Ans: This address is lower than 135.45.56.0/22. The default course will be utilized and the bundle will be directed out over Router 2.

d. 192.53.40.7

Ans: 192.53.40.7 and 255.255.254.0= 192.53.40.0. It matches 192.53.40.0/23 steering section and the bundle will be directed out over Router1.

e. 192.53.56.7

Ans: 192.53.56.7 and 255.255.254.0= 192.53.56.0. The default course will be utilized and the parcel will be steered out over Router 2.

2 ANS:Each part of the first IP datagram ought to contain the same IP part ID esteem. The incentive in this field will help a collector so it can relate and reassemble an arrangement of sections in like manner to a unique datagram back together. Circumstantially, the part balance will help put the pieces in the right request and the greater piece (MF) banner will tell the beneficiary when it has achieved the last part (the MF banner will be set to zero).

3 ANS: TTL, Header checksum

4 ANS:IP Address Classes: IP tending to backings three distinctive business address classes; Class A, Class B, and Class C. In a class An address, the main octet is the system parcel, so the class An address of, 10.1.25.1, has a noteworthy system address of 10. Octets 2, 3, and 4 (the following 24 bits) are for the hosts.