A company pays its salespeople on a commission basis. The salespeople each recei

Question

A company pays its salespeople on a commission basis. The salespeople each receive $200 per week plus 9 percent of their gross sales for that week. For example, a salesperson who grosses $5000 in sales in a week receives $200 plus 9 percent of$5000,or a total of $650. Write a program (using an array of counters) that determines how many of the salespeople earned salaries in each of the following ranges (assume that each salesperson’s salary is truncated to an integer amount): a)$200–299 b)$300–399 c)$400–499 d) $500–599 e) $600–699 f) $700–799 g) $800–899 h) $900–999 i) $1000 and over.
NOTE: Please use pointers instead of a static array.

Explanation / Answer

using namespace std;
#include <iostream>
#include <string>
int main()
{

int *sales;
int *salaries;

int *count
int n;
cout<<"enter how many employess :";
cin>>n;
for(int i=0;i<n;i++)
{
cout<<" enter sales of employee "<<i+1<<":";
cin>>*(sales+i);
*(salaries+i)=200+((int)(0.09**(sales+i)));
if(*(salaries+i)>=200&&*(salaries+i)<=299)
*(count+0)++;
else if(*(salaries+i)>=300&&*(salaries+i)<=399)
*(count+1)++;
else if(*(salaries+i)>=400&&*(salaries+i)<=499)
*(count+2)++;
else if(*(salaries+i)>=500&&*(salaries+i)<=599)
*(count+3)++;
else if(*(salaries+i)>=600&&*(salaries+i)<=699)
*(count+4)++;
else if(*(salaries+i)>=700&&*(salaries+i)<=799)
*(count+5)++;
else if(*(salaries+i)>=800&&*(salaries+i)<=899)
*(count+6)++;
else if(*(salaries+i)>=900&&*(salaries+i)<=999)
*(count+7)++;
else if(*(salaries+i)>=1000)
*(count+8)++;
}
for(int i=0;i<9;i++)
{
cout<<" Category "<<i+1<<" : "<<*(count+i);
}

return 0;
}

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