This is my second time posting please only answer IF YOU ARE GOOD AT MATLAB PLEA

Question

This is my second time posting please only answer IF YOU ARE GOOD AT MATLAB PLEASE. The code I have is almost complete but I need it to run for if n= 10 correctly. I NEED AN IF ELSE STATMENT. included but i need help getting it. please do not post answer until your output matches this;;

n = 10; correct = [0 1 0 1 0 1 0 1 0 1]; and n = 11; correct = [1 0 1 0 1 0 1 0 1 0 1]; Write a function that takes in a number, n, as an input and has one output, an array of n that alternates 1's and 0's. IF the length of the array is odd, start the array with a 1. lf the length of the array is even, start the array with a 0. Please use a loop to accomplish this For example: [array] alternating (10) Would return the array: array [0 1 0 1 0 1 0 101] While array alternating (11) Would return the array array [1 0 1 0 1 0 1 0101] You can use the mod function to determine whether a number is even or odd. mod(n,2) will return 1 if n is odd and 0 if n is even My Solutions Try Again Activity Summary You have submitted: 6 solutions Maximum Submissions: Unlimited solutions Most recent best submission: 6th Submission: 1 out of 3 tests passed Test Results Submitted on 21 Feb 2017 at 4:22 Solution ID: 3648352 function array alternating (n) array rand (1, n) for i 1 n array (i) mod (i,2); end end

Explanation / Answer

function lst = alternating(n)
lst = zeros(1,n);
if mod(n,2) == 1
for i = 1:2:n
lst(1,i)=1;
end
else
for i = 2:2:n
lst(1,i)=1;
end
end
end
alternating(10)
alternating(11)

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