The variation of vapor pressure p (in units of mm Hg) of benzene with temperatur

Question

The variation of vapor pressure p (in units of mm Hg) of benzene with temperature in the range of 0 lessthanorequalto T lessthanorequalto 42 degree C can be modeled with the equation (Handbook of Chemistry and Physics, CRC Press) log_10P = b - 0.05223a/T where a = 34172 and b = 7.9622 are material constants and T is absolute temperature (K). Write a program in a script file that calculates the pressure for various temperatures. The program should create a vector of temperatures from T = 0 degree C to T = 42 degree C with increments of 2 degrees, and display a two- column table p and T, where the first column temperatures in degree C, and the second column the corresponding pressures in mm Hg.

Explanation / Answer

MATLAB CODE:

temp=zeros(1,22);   
press=zeros(1,22);
k=2;
for i=2:2:42 %For taking temperature values in array   
temp(k)=i;
k=k+1;
end
for i=1:22
r=7.9622-((0.05223*34172)/(temp(i)+273)); %caculating pressure
press(i)=10^r;
end
disp(temp);
disp(press);

Output:

Columns 1 through 20

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38

Columns 21 through 22

40 42

Columns 1 through 12

26.5741 29.6487 33.0268 36.7328 40.7930 45.2349 50.0877 55.3825 61.1518 67.4302 74.2541

81.6617

Columns 13 through 22

89.6934 98.3914 107.8003 117.9666 128.9392 140.7692 153.5100 167.2175 181.9501 197.7684

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