perimerter = s x n where n number of sides s length of a side apothem = s/2tan (

Question

perimerter = s x n where n number of sides s length of a side apothem = s/2tan (180/n)
area = apothem x perimeter /2
write a matlab scipt to determine the side length of a regular polygon given the numbers of sides and the are
area = ? number of sides = ? side length = ? perimerter = s x n where n number of sides s length of a side apothem = s/2tan (180/n)
area = apothem x perimeter /2
write a matlab scipt to determine the side length of a regular polygon given the numbers of sides and the are
area = ? number of sides = ? side length = ? perimerter = s x n where n number of sides s length of a side apothem = s/2tan (180/n)
area = apothem x perimeter /2
write a matlab scipt to determine the side length of a regular polygon given the numbers of sides and the are
area = ? number of sides = ? side length = ?

Explanation / Answer

%%save as polygonarea.m

%%The script file that takes number of sides

%%side lenght as arguments and calcualtes

%%area of polygon and store in area

function area=polygonarea(numSides, lenSide)

%%calculate perimeter

perimeter=numSides*lenSide;

%%convert radians to degress

angle=180*3.1415/180;

%%calculate apothem

apothem=lenSide/(2*tan(angle/numSides));

%%calculate area

area=(perimeter*apothem)/2;

-----------------------------------------------------------------------------

-----------------------------------------------------------------------------

Note : Run the script file name from the matlab command prompt

Sample output:

where 6 is number of sides, 10 is the lengt of the side.

--> polygonarea(6,10)
ans =
259.8169
-->

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