You will develop a web server that handles one HTTP request at a time. Your web

Question

You will develop a web server that handles one HTTP request at a time. Your web server should accept and parse the HTTP request, get the requested file from the server’s file system, create an HTTP response message consisting of the requested file preceded by header lines, and then send the response directly to the client. If the requested file is not present in the server, the server should send an HTTP “404 Not Found” message back to the client.

Code

Below you will find the skeleton code for the Web server. You are to complete the skeleton code. The places where you need to fill in code are marked with #Fill in start and #Fill in end. Each place may require one or more lines of code.

Skeleton Python Code for the Web Server

#import socket module

from socket import *

import sys # In order to terminate the program

serverSocket = socket(AF_INET, SOCK_STREAM)

#Prepare a sever socket

#Fill in start

#Fill in end

while True:

    #Establish the connection

    print('Ready to serve...')

    connectionSocket, addr = #Fill in start              #Fill in end         

    try:

        message =   #Fill in start          #Fill in end               

        filename = message.split()[1]                

        f = open(filename[1:])                       

        outputdata = #Fill in start       #Fill in end                  

        #Send one HTTP header line into socket

        #Fill in start

        #Fill in end               

        #Send the content of the requested file to the client

        for i in range(0, len(outputdata)):          

            connectionSocket.send(outputdata[i].encode())

        connectionSocket.send(" ".encode())

        connectionSocket.close()

    except IOError:

        #Send response message for file not found

        #Fill in start       

        #Fill in end

        #Close client socket

        #Fill in start

        #Fill in end           

serverSocket.close()

sys.exit()#Terminate the program after sending the corresponding data

When you are going to write the code, please stick to this format.

Explanation / Answer

import sys

serverPort=9876

while True:

serverSocket = socket(AF_INET, SOCK_STREAM)

serverSocket.bind((”,serverPort))
serverSocket.listen(1)

try:

message = connectionSocket.recv(1024)

filename = message.split()[1]                

f = open(filename[1:])                       

outputdata = f.read()

print outputdata

connectionSocket.send(‘ HTTP/1.1 200 OK ’)

for i in range(0, len(outputdata)):          

connectionSocket.send(outputdata[i].encode())

connectionSocket.send(" ".encode())

connectionSocket.close()

except IOError:

connectionSocket.send(‘Error 404: File not found’)
connectionSocket.close()
serverSocket.close()

sys.exit()

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