Write a C program to run on terminal find the count of words and optionally the

ID: 3793150 • Letter: W

Question

Write a C program to run on terminal find the count of words and optionally the longest and or shortest words in a string input by the user or coming from a file. If there is no filename the user would enter the string right after running the command. You must use getopt to parse the command line. Usage: words [-l] [-s] [filename] The l flag means to find the longest and the s option means to find the shortest. You may have both or one of the flags. Output should be well formatted and easy to read.

Explanation / Answer

# include <stdio.h>

# include <string.h>

# include <stdlib.h>

char flag = '-'; char in[100];

void displayMenu();

int countLongestWords(char in[100]);

int countShortestWords(char in[100]);

void getInput();

int getStringLength();

int main() { int term; getInput();

displayMenu();

scanf("%c",&flag);

if(flag == 'I'|| flag == 'i')

{

printf("%i","Longest Words: " ,countLongestWords(in));

}

else if(flag == 'S' || flag == 's')

{

printf("%i","Shortest Words: " ,countShortestWords(in));

}

return 0;

}

void getInput()

{

int count = -0;

char c = '-';

int i;

printf(" Please input the string: ");

gets(in);

}

void displayMenu()

{

printf(" Please Select the flag from the followings: ");

printf(" I for longest Words S for shortest words ");

}

int getStringLength() { return strlen(in);

}

int countLongestWords(char input[100])

{

char temp[100], temp2[100], temp3[100];

int count = -1; int i, len = getStringLength();

for(i=0; i<len; i++)

{

if(input[i] != 32 && input[i] != '')

{

temp[i] = input[i];

}

strcpy(temp3, temp2);

strcpy(temp2, temp);

if(strlen(temp3)>strlen(temp))

count++;

}

return count;

}

int countShortestWords(char input[100])

{

char temp[100], temp2[100], temp3[100];

int count = -1;

int i, len = getStringLength();