This C program needs to read a file containing integers (up to 1000 ints). The f

Question

This C program needs to read a file containing integers (up to 1000 ints). The file will be classified as an array and the data needs to be sorted using an odd-even sort (smallest to largest). After that, a user will search the index and the output should return the integer that is inside that index which the user search. (i.e. a file containing integers(4 18 1 24 12)----> This file will be sorted using odd-even sort(1,4, 12, 18, 24)---->The program will ask the user to enter an index --> User enters index --> Output should display what number is in that index --> enter another index again ---> display --> If user enters -1, program will exit).

Explanation / Answer

#include <stdio.h>
#include <stdlib.h>

int main()
{

FILE *numFile;
numFile = fopen("numbers.txt", "r");

//reading numebrs into array from file
int numbers[1000];
int i,j,temp,index;

if (numFile == NULL)
{
printf("Error occured in reading file ");
exit (0);
}
   // reading each number
for (i = 0; i < 1000; i++)
{
fscanf(numFile, "%d,", &numbers[i] );
}
  
   // sorting numbers ascending order
   for (i = 0 ; i < ( n - 1 ); i++)
{
       for (j = 0 ; j < n - i - 1; j++)
       {
           if (numbers[j] > numbers[j+1]) /* For decreasing order use < */
           {
               temp = numbers[j];
               numbers[j] = numbers[j+1];
               numbers[j+1] = temp;
           }
       }
}
  
   //reading index and dispaly value
   while(1){
       printf("Enter index value (-1 to exit): ");
       scanf("%d",&index);
       if(index < 0){
           break; // for negative values
       }
       else{
           printf("Value at index %d is %d",index,numbers[index]);
       }
   }
   // closing each file
fclose(numFile);

return 0;
}

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