(This is a follow up to my previous question) (I already asked this part) 1) Ima

Question

(This is a follow up to my previous question)

(I already asked this part)

1) Imagine the length of a 10Base5 cable is 2500 meters. If the speed of propagation in a thick coaxial cable is 200,000,000 meters/second, how long does it take for a bit to travel from the beginning to the end of the network? Ignore any propagation delay in the equipment.

(So here is the question)

2) Using the data in exercise 1, Find the maximum time it takes to sense a collision. The worst case occurs when data are sent from one end of the cable and the collision happens at the other end. Remember that the signal needs to make a round trip.

Explanation / Answer

I will answer both 1 & 2 so that it will be better understood:-

1) Since the length of a 10Base5 cable is 2500 meters which means there will be 4 break points [4 repeaters]
-----*------*-----*------*-----
This completes my 2500 m . Each at 500 distance [* is repeater].
Actually repeaters would add Propagation delay . As it is mentioned in the question to ignore propagation delay,
So Time it take for a bit to travel from the beginning to the end of the network :
2500 m / 200,000,000 m/s = 1.25 x 10 -6   or 12.5 µs

2) The worst case occurs when data are sent from one end of the cable and the collision happens at the other end.
The answer is in the question itself . For collision to get detected in the worst time , the signal will traverse the whole network twice

Maximum time it takes to sense a collision = 2*12.5 µs = 25 µs.

Thanks, Let em know if there is any concern.

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