write a \'c\' program for each problems seperately, PROBLEM 1: Declare a variabl

Question

write a 'c' program for each problems seperately,

PROBLEM 1:

Declare a variable of type float
Assign it the value 3.6
Print it to ten decimal places

PROBLEM 2:

Declare a variable of type float
Assign it the value 1.0/10.0 (exactly as shown here)
Print it to ten decimal places

PROBLEM 3:

Declare a variable of type double
Assign it the value 1/2 (exactly as shown here)
Print it
Assign it the value 1.0/2.0 (exactly as shown here)
Print it

PROBLEM 4:

Declare a variable of type double
Assign it the value 9999999.4499999999 (exactly as shown here)
Print it
Cast it to a float
Print the float

PROBLEM 5:

Declare a variable of type int
Assign it the value 30000*30000 (exactly as shown here)
Print it
Assign it the value 40000*40000 (exactly as shown here)
Print it
Assign it the value 50000*50000 (exactly as shown here)
Print it
Assign it the value 60000*60000 (exactly as shown here)
Print it

PROBLEM 6:

Use floats for this problem
Assign the value 1e20 to a float and print it
Assign the value (1e20 + 3500000000) to a float and print it
Assign the value (1e20 + (3500000000 * 1000000000)) to a float and print it
Declare a variable of type float
Assign it the value of 1e20
Use a loop to add 3500000000 to that variable 1000000000 times.
Print the result after the loop
Note: Don't just multiply then add for that last part above. Use a loop to add 3500000000 at each iteration

Explanation / Answer

Problem 1:

#include <stdio.h>

int main() {
   float value;
   value = 3.6;
   printf("%.10f ", value);
   return 0;
}

Problem 2:

#include <stdio.h>

int main() {
   float value;
   value = 1.0/10.0;
   printf("%.10f ", value);
   return 0;
}

Problem3:

#include <stdio.h>

int main() {
   double value;
   value = 1/2;
   printf("%f ", value);
  
   value = 1.0/2.0;
   printf("%f ", value);
  
  
   return 0;
}

Problem 4:

#include <stdio.h>

int main() {
   double value;
   value = 9999999.4499999999;
   printf("%f ", value);
   float casted_value = (float) value;
   printf("%f ", casted_value);
  
  
   return 0;
}

Problem 5:

#include <stdio.h>

int main() {
   int value;
   value =30000*30000;
   printf("%d ", value);
  
   value =40000*40000;
   printf("%d ", value);
  
   value =50000*50000;
   printf("%d ", value);
  
   value =60000*60000 ;
   printf("%d ", value);
  
   return 0;
}

Problem 6:

#include <stdio.h>

int main() {
   float value;
   value =1e20;
   printf("%f ", value);
  
   value =(1e20 + 3500000000);
   printf("%f ", value);
  
   value =(1e20 + (3500000000 * 1000000000));
   printf("%f ", value);
  

value = 1e20;
int i;
for (i = 0; i < 1000000000 ; i++)
{
value = value + 3500000000;
}
printf("%f ", value);
  
   return 0;
}

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